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zhannawk [14.2K]
3 years ago
11

Area of rectangle and traingle Please helpp

Mathematics
2 answers:
mina [271]3 years ago
3 0

Step-by-step explanation:

here \: is \: your \: solution \\  \\ base \:  = 4 \: cm \\  \\ height \:  = 6 \: cm \\  \\ area \: of \: traingle = (1 \div 2) \times base \times height \\  \\ area \:  = (4 \times 6) \div 2 \\  \\ area = 12 \: cm.sq \\  \\ hope \: it \: helps

Lelechka [254]3 years ago
3 0

Answer: a

Step-by-step explanation:

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Extraneous solutions are the values that we get when solving equations which aren't really solutions to the equation.

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What is NOT a way to write 52 + 80? 50 + 2 + 80 (50 + 80) + 2 50 + 80 + 2 + 8 50 + 2 + 80 + 0
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Step-by-step explanation:

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3 years ago
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Answer:

Step-by-step explanation:

y = (x^2 + 4x)      + 2

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Put it after 4x

y = (x^2 + 4x + 4)   +2  Subtract what you put inside the brackets on the outside.

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Let's simplify the following expression:

\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}

We get,

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