Answer:
625 ft^2
Step-by-step explanation:
Given
--- perimeter
Required
The largest area
The perimeter is calculated as:
So, we have:
Divide both sides by 2
Make L the subject
The area is calculated as:
Substitute
Open bracket
Differentiate with respect to W
Set to 0; to get the maximum value of W
Collect like terms
Divide by -2
So, the maximum area is:
Answer:
B. x < -8 or x > 8
Step-by-step explanation:
You can use process of elimination to solve this problem by going through every solution and testing them out, but let's jump right to B.
Process:
You know that since the inequality states that x^2 has to be greater than 64, x has to be more than 8, or less than -8.
This is because 8^2 = 64, and -8^2 = 64, and the inequality requires the answer to be more than 64.
Looking at B., you can see that if x is < -8, the square of, for example, -9, would be 81. This is greater than 64, so this works!
Now, B. also has an alternative. The 'or' is a major clue to which is the correct answer, since the square root of any number can be positive or negative. (-8^2 = 8^2)
The 'or' states that x must be greater than 8. So, for example, if we take the square of 10, we get 100, and that is also greater than 64.
We've proven that this solution is accurate for both parts, so it is definitely the one we want!
Hope this helps!
Cos²(x) + sin²(x)
¹/₂[1 - cos(2x)] + ¹/₂[1 + cos(2x)]
[¹/₂ - ¹/₂cos(2x)] + [¹/₂ + ¹/₂cos(2x)]
¹/₂ + ¹/₂ - ¹/₂cos(2x) + ¹/₂cos(2x)
1
Answer:
C
Step-by-step explanation:
