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nignag [31]
3 years ago
5

Andrew had 30 dollars to spend on 3 gifts. He spent 8

Mathematics
1 answer:
amm18123 years ago
8 0

Andrew has 17 dollars left for gift c

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Lif a/b =⅔ find the value of 2a²+3b²/a²+b²<br>​
Contact [7]

Answer:

95/4

Step-by-step explanation:

Given,

a/b =2/3

Therefore, 2a²+3b²/a²+b² = ?

We get,

a/b = 2/3

So, we can write

a = 2 and b = 3

Now,

2×(2)² + 3×(3)²/(2)² + (3)² [Putting the values of a and b]

= 2×4 + 3×9/4 + 9

= 8 +27/4 + 9

= (32+27+36)/4 [ Taking L.C.M, we get 4]

= 95/4

4 0
3 years ago
Please... I need help! ​<br>Some one to explain me plz
SVETLANKA909090 [29]
What am I supposed to be helping with the picture you took is only showing examples
7 0
3 years ago
Read 2 more answers
NEED ANSWERED ASAP PLEASE<br> sin(0)= -4 sqrt 29 / 29
VladimirAG [237]

Answer:

Is - 4

Step-by-step explanation:

29/29  cancel it out

so it will leave -4 out

3 0
3 years ago
Which equation involves a prime quadratic and cannot be solved by factoring?
brilliants [131]
B. x^2 + 5x - 4 = 0

Anyway that you try to factor it will not work

~~hope this helps~~
6 0
3 years ago
If 65 percent of the population of a large community is in favor of a proposed rise in school taxes, approximate the probability
xz_007 [3.2K]

Answer:  a) 0.99917  b)  0.7054  c) 0.9820

Step-by-step explanation:

Let X denotes the number of people are in favor of a proposed rise in school taxes.

Era re given that p(probability that a person is in favor of a proposed rise )= 0.65

Sample size : n= 100

Mean= np = 100(0.65)=65

Standard deviation: \sigma=\sqrt{np(1-p)}\\\\=\sqrt{100(0.65)(0.35)}\\\\=4.76969600708\approx4.77

a) Now, the probability that a random sample of 100 people will contain  at least 50 who are in favor of the proposition :

P(x\geq50)=P(\dfrac{x-\mu}{\sigma}\geq\dfrac{50-65}{4.77})\\\\=P(z\geq-3.144)\\\\=P(z-z)=P(Z

b) between 60 and 70 inclusive who are in favor;

P(60

c) fewer than 75 in favor.

P(x

3 0
3 years ago
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