Answer:
Domain: -4 < x < 4
Zeros: (-2, 0), (0, 0) and (2, 0)
The function is positive if: 0 < x < 2
The function is negative if: -4 < x < 0 and 2 < x < 4
Step-by-step explanation:
Domain of the function are those x values where the function is defined, For this case, -4 < x < 4
Zeros of a function are those x values where y = 0, that is, the graph intersect x-axis. For this case, the points are: (-2, 0), (0, 0) and (2, 0)
The function is positive if the graph o the function is above x-axis. For this case, the function is positive at the interval (0, 2)
The function is negative if the graph o the function is below x-axis. For this case, the function is negative at the intervals (-4, 0) and (2, 4)
Answer:
What other answer?
Step-by-step explanation:
Answer: 
Explanation:
Please follow the diagram in attachment.
As we know median from vertex C to hypotenuse is CM
We are given length of CG=4
Median divide by centroid 2:1
CG:GM=2:1
Where, CG=4
ft
Length of CM=4+2= 6 ft
In 
Using trigonometry ratio identities
ft
ft
ft
In 
Using pythagoreous theorem
Length of AG=2/3 AN
ft
Answer:
3(x + 2)(2x - 5)
Step-by-step explanation:
Given
6x² - 3x - 30 ← factor out 3 from each term
= 3(2x² - x - 10) ← factor the quadratic
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 2 × - 10 = - 20 and sum = - 1
The factors are + 4 and - 5
Use these factors to split the x- term
2x² + 4x - 5x - 10 ( factor the first/second and third/fourth terms )
= 2x(x + 2) - 5(x + 2) ← factor out (x + 2) from each term
= (x + 2)(2x - 5), thus
2x² - x - 10 = (x + 2)(2x - 5) and
6x² - 3x - 30
= 3(x + 2)(2x - 5) ← in factored form
