What is the standard form of y-7=-2(x+1)

Mathematics

1 answer:

densk [106]2 years ago

7 0

The standard form is 2x+y=5

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What is the slope of this graph? a. 4 b. -4 c. -1/4 d. 1/4

kykrilka [37]

The answer is -4 i just did the test

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3 years ago

The degree of the function f(x) = -(x + 1)2(2x - 3)(x + 2)2 is , and its y-intercept is

Serggg [28]

Answer:

Degree = 5

Y intercept = 12

Step-by-step explanation:

our function is given as

$f(x)=-(x+1)^2 \cdot (2x-3) \cdot (x+2)^2$

in the above polynomial our variable is x and it is being multiplied for 5 times. Hence the probable degree for the above polynomial is 5

In order to find the y intercept , we need to put x=0 in f(x) as y intercept is the point at which the function graphically meets y axis and where x = 0

Hence

$f(0)=-(0+1)^2 \cdot (2(0)-3) \cdot (0+2)^2$

$f(0)=-(1)^2 \cdot (0-3) \cdot (2)^2$

$f(0)=-1 \cdot (-3) \cdot 4$

$f(0)=3 \cdot 4$

$f(0)=3 \times 4$

$f(0)=12$

Hence the y intercept is 12 units

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3 years ago

What is the slope of the line represented by the table below?

gayaneshka [121]

9/5

If you choose two points you can find the equation change in y/change in x (y2-y1)/(x2-x1). Using the first two points this looks like:

(49-22)/(25-10)=27/15=9/5

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3 years ago

If x2 = 30, what is the value of x? A. ±60 B. ±15 C. ±square root of 30 D.±square root of 15

anygoal [31]

Answer:

C. ±square root of 30

Step-by-step explanation:

Apply the square root function to both sides of the equation:

$\sqrt{x^2}=\sqrt{30}\\\\|x|=\sqrt{30}\\\\x=\pm\sqrt{30}$