Answer:
Yes, because by dividing x by his equivalent y, you find a constant of proportionality being 10.
x / y = 10
Step-by-step explanation:
20 / 2 = 10
50 / 5 =10
60 / 6 = 10
70 / 7 = 10
Shaded area = area of the hexagon – area of the pentagon + area of the square – area of the equilateral triangle. This can be obtained by finding each shaded area and then adding them.
<h3>Find the expression for the area of the shaded regions:</h3>
From the question we can say that the Hexagon has three shapes inside it,
Also it is given that,
An equilateral triangle is shown inside a square inside a regular pentagon inside a regular hexagon.
From this we know that equilateral triangle is the smallest, then square, then regular pentagon and then a regular hexagon.
A pentagon is shown inside a regular hexagon.
- Area of first shaded region = Area of the hexagon - Area of pentagon
An equilateral triangle is shown inside a square.
- Area of second shaded region = Area of the square - Area of equilateral triangle
The expression for total shaded region would be written as,
Shaded area = Area of first shaded region + Area of second shaded region
Hence,
⇒ Shaded area = area of the hexagon – area of the pentagon + area of the square – area of the equilateral triangle.
Learn more about area of a shape here:
brainly.com/question/16501078
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Answer:
(c) (3, 3)
Step-by-step explanation:
Point E partitions both the x-distance and the y-distance in the ratio 2 : 1. That is, for either the x-coordinates or the y-coordinates, ...
CE : ED = 2 : 1
Try the answers with the x-coordinates.
CE : ED = (1 -(-1)) : (5 - 1) = 2 : 4 . . . . incorrect
CE : ED = (-3 -(-1)) : (5 -(-3)) = -2 : 8 . . . . incorrect
CE : ED = (3 -(-1)) : (5 -3) = 4 : 2 = 2 : 1 . . . . correct
CE : ED = (-1 -(-1)) : (5 -(-1)) = 0 : 6 . . . . incorrect
The only viable choice is (3, 3).
_____
<em>Alternate solution</em>
For a partitioning of m : n, the desired point is ...
E = (n×C +m×D)/(m+n)
For partitioning of 2 : 1, the desired point is ...
E = (1×(-1, -3) + 2×(5, 6))/(2+1) = (-1+10, -3 +12)/3
E = (3, 3)
M = - 7 - 3 / - 2 - 4
m = - 10 / - 6
m = 10/6
m = 5/3
y = 5/3x + c , (4,3)
3 = 5/3(4) + c
12 = 20 + 4c
4c = - 8
c = - 2
y = 5/3x - 2
i am a mathematics teacher. if anything to ask please pm me
Answer:
D. false; if a = 1, b = 2, and c = 3, then 1(2 + 3) ≠ 1(2) + 2(3)
Step-by-step explanation:
A is false, because the a is being distributed/ being multiplied to all terms inside the parenthesis, and not the term b.
B is also false. There is no indicated negative signs.
C is also false because 1(1 + 1) is EQUAL to 1(1) + 1(1)
D is true.
