If 3 pounds of apples cost $1.89 how much do 5 pounds cost
2 answers:
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<h3>Answer: n = -11</h3>
The other choices are false, so choice C is the only solution here.
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Explanation:
Draw a number line. You'll have 0 in the center, with positive values on the right. The positive values increase 1,2,3,4,... as you move from left to right.
The negative values will go in the opposite direction. When going from right to left, we have -1, -2, -3, -4, ...
See the diagram below.
Now plot an open hole at -7 on the number line. The open hole says that we exclude this value from the solution set. Then we shade everything to the left of the open circle. This visually describes all values smaller than -7. Something like -2 is not to the left of -7, meaning -2 < -7 is false. But a value like -10 is to the left of -7, making -10 < -7 true.
With that in mind, the answer is n = -11 since -11 is to the left of -7. Of the values in the answer choices, it's the only thing to the left of -7.
The value n = -7 cannot be the solution because n < -7 would become -7 < -7 which is false.
Answer:
The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.
Step-by-step explanation:
According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.
Then, the mean of the distribution of sample mean is given by,
And the standard deviation of the distribution of sample mean is given by,
The information provided is:
<em>μ</em> = 144 mm
<em>σ</em> = 7 mm
<em>n</em> = 50.
Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.
Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:
*Use a <em>z</em>-table for the probability.
Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.