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3 years ago

15

Pls help and show workings (If you don’t know the answer please don’t respond)

2 answers:

raketka [301]3 years ago

8 0

Answer:

the required postulate which should be used here to make the triangles congruent is

C. ASA , okay

Step-by-step explanation:

because, one side and one angle of both triangles are equal and one of angles of the both triangles are vertically opposite angles , hence they are also equal , so we get an angle, a side and one another angle equal to corresponding side and angles of other triangles , so required postulate is C. ASA

I hope it helped

kogti [31]3 years ago

5 0

Answer:

ASA

Step-by-step explanation:

you have 2 angles and a side, so it could either be ASA or AAS.

ASA- the side is between 2 angles (image 1)

AAS- I'm not exactly sure how to describe it, but it's like 2 angles without a side between (image 2)

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Answer:

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Step-by-step explanation:

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3 years ago

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evablogger [386]

Answer:

Factoring the expression $xy^4+x^4y^4$ completely we get $\mathbf{xy^4(x+1)(x^2-x+1)}$

Step-by-step explanation:

We need to factor the expression $xy^4+x^4y^4$ completely

We need to find common terms in the expression.

Looking at the expression, we get $xy^4$ is common in both terms, so we can write:

$xy^4+x^4y^4\\=xy^4(1+x^3)$

So, taking out the common expression we get: $xy^4(1+x^3)$

Now, we can factor the term (1+x^3) or we can write (x^3+1) by using formula:

$a^3+b^3=(a+b)(a^2-ab+b^2)$

So, we get:

$xy^4(1+x^3)\\=xy^4(x^3+1)\\Applying\:the\:formula\;of\:a^3+b^3\\=xy^4(x+1)(x^2-x+1)$

Therefor factoring the expression $xy^4+x^4y^4$ completely we get $\mathbf{xy^4(x+1)(x^2-x+1)}$

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Step-by-step explanation:

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