We need to find the surface area and volume for each rectangular prism. Here are the formulas I'm going to plug each prism's measurements.
S.Area=2(lw+wh+lh)
Volume: lwh
Question 75:
Volume: 3×1×3=9 cm³
Surface Area= 2(3)+2(3)+2(9)=6+6+18=30 cm²
Question 76:
Volume: 6×2×5=60 ft.³
Surface Area: 2(12)+2(10)+2(30)=24+20+60=104 ft²
Question 77:
Volume: 4×2×6=48 m³
Surface Area: 2(8)+2(12)+2(24)=16+24+48=88 m²
Step-by-step explanation:
Hey, there!!
Let's simply work with it,
60° + 2x° + (2x+12)° = 180° { being a linear pair}.
or, 72° + 4x = 180°
4x = 180° - 70°

Therefore, the value of x is 27°.
Now,
2x° = (2×27)°= 54°
(2x+12)° = 2×27°+12°= 66°.
(x+2)= 27+ 2= 29°
Now, The left angle is 27°.
Therefore, The answer is option A.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
Option E is correct.
The expected number of meals expected to be served on Wednesday in week 5 = 74.2
Step-by-step Explanation:
We will use the data from the four weeks to obtain the fraction of total days that number of meals served at lunch on a Wednesday take and then subsequently check the expected number of meals served at lunch the next Wednesday.
Week
Day 1 2 3 4 | Total
Sunday 40 35 39 43 | 157
Monday 54 55 51 59 | 219
Tuesday 61 60 65 64 | 250
Wednesday 72 77 78 69 | 296
Thursday 89 80 81 79 | 329
Friday 91 90 99 95 | 375
Saturday 80 82 81 83 | 326
Total number of meals served at lunch over the 4 weeks = (157+219+250+296+329+375+326) = 1952
Total number of meals served at lunch on Wednesdays over the 4 weeks = 296
Fraction of total number of meals served at lunch over four weeks that were served on Wednesdays = (296/1952) = 0.1516393443
Total number of meals expected to be served in week 5 = 490
Number of meals expected to be served on Wednesday in week 5 = 0.1516393443 × 490 = 74.3
Checking the options,
74.3 ≈ 74.2
Hence, the expected number of meals expected to be served on Wednesday in week 5 = 74.2
Hope this Helps!!!
Answer:
13, 8, 3
Step-by-step explanation:
Subtract 5 from the following terms.
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