The rule is x+2, y-3 so you apply it to each of these coordinates. Right 2, down 3.
A(-2,2) -> A'(0,-1)
B(-2,4) -> B'(0, 1)
D(2,2) -> D'(4,-1)
2(7/2)^x = 49/2
Divide both sides by 2:
(7/2)^x = 49/4
I notice that 49/4 can be rewritten as (7/2)^2, so we now have:
(7/2)^x = (7/2)^2
The only way for this to be true is if x = 2. Thus, we are done.
C) Length of 7 and Width of 4. This is because 14 x 2 is 28, and 7 x 4 is 28 as well.
I hope this Helps!
I've done the first four questions. Use this method to answer the rest. For an odd number of objects find the cost of one and multiply by how many you are asked to find.
A median intersects at the midpoint of the opposite length. The midpoint is:
x,m = (4+-2)/2 = 1
y,m = (-1+7)/2 = 3
The midpoint is at (1,3). With this point and point R(9,9), the equation would be:
y = mx + b, where
m = (9 - 3)/(9 - 1) = 0.75
b is the y-intercept
Substituting any point,
3 = 0.75(1)+b
b = 2.25
Thus, the equation for the median is:
y = 0.75x + 2.25
