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3 years ago

50 POINTS !! PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.

Mathematics

2 answers:

Sergio039 [100]3 years ago

8 0

Answer:

sqrt41

Step-by-step explanation:

a^2+b^2=c^2

25+16=41

sqrt41

Dima020 [189]3 years ago

7 0

Answer:

6.40312

Step-by-step explanation:

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4 years ago

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There are 9 students in a class: 2 boys and 7 girls. If the teacher picks a group of 4 at random, what is the probability that e

notsponge [240]

Answer:

<h2>28% probability that every student in the group is a girl.</h2>

Step-by-step explanation:

In this problem we have independent events, that is, the event "picking a girl" doesn't affect an "picking a boy", also, picking picking a girl doesn't affect the probability of the other subjects.

So, the probability when the first girl is being picked is:

$P_{1}=\frac{7 \ girls}{9 \ students}$

Because among the total 9 students, there are 7 girls.

Now, after picking one girl, there remains 6 girls and 8 students to be picked. So, the probability of the second girl would be:

$P_{2}=\frac{6 \ girls}{8 \ students}$

Then, the probability of the third girl:

$P_{3}=\frac{5 \ girls}{7 \ students}$

The fourth girl probability:

$P_{3}=\frac{4 \ girls}{6 \ students}$

Therefore, the probability of picking all 4 girls would be the product of each probability, because events are independent (we use product when they are independent):

$P=\frac{7 \ girls}{9 \ students} \times \frac{6 \ girls}{8 \ students} \times \frac{5 \ girls}{7 \ students} \times \frac{4 \ girls}{6 \ students}\\P=\frac{5}{18}=0.28 \ (or \ 28\%)$

Therefore, there's 28% probability that every student in the group is a girl.

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3 years ago

Word problems<br><br>kind of urgent

seraphim [82]

838. = 27x-271.42
+271.42. +271.42
1109.42= 27x
Divide by 27
X= $41.0896 per hour

5. Gross Pay is what you make before they takes taxes and insurance. From your check.
So Net Pay is better because what you actually get.

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3 years ago