Answer:
1
Step-by-step explanation:
Answer: 4 quarts
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58-18=40
40/2=20
20
20+18=38
Answer is 38 & 20
The distance from the center of dilation, P, to.the image vertice S' is; 6 units.
<h3>What is the distance from the center of dilation, P, to the image S'?</h3>
It follows from the task content that the center of dilation of the triangle QRS is point P and the length of segment PS in the pre-image is; 8 units.
Ultimately, since the dilation factor is; three-fourths, it therefore follows that the distance of point P to S' in the image is; (3/4) × 8 = 6 units.
Read more on dilation;
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