The equation for maximum number of days (x) Zoey can afford to rent while saving within her budget is 350 > 20 + 42.72x
The given parameters;
cost per day = $42.72
cost per mile, = $0.10
distance planned by Zoey = 200 miles
maximum amount to be spent by Zoey = $350
The maximum number of days (x) Zoey can afford to rent while saving within her budget is calculated as follow;
<em>Total expenses should be less than her maximum budget</em>
<em />
200(0.1) + 42.72x ∠ 350
20 + 42.72x ∠ 350
The above equation can also be written as; 350 > 20 + 42.72x
Thus, the equation for maximum number of days (x) Zoey can afford to rent while saving within her budget is 350 > 20 + 42.72x
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Answer:
1.6 or 8/5.
Step-by-step explanation:
(-2/5)/(-1/4)
(-2/5)(-4)
=1.6 or 8/5.
Answer:
income=2*expenses-100
Step-by-step explanation:
income=a*expenses+b
a:slope
a=(income of 1 - income of 0)/(expenses of 1 - expenses of 0)
=(10-0)/(55-50)=10/5=2
income=2*expenses+b
for product 0
income=0
expenses=50
》0=2*(50)+b
b=-100
income=2*expenses-100
The answer to this question is that this is a rhombus
since it has a diameter of 6, its radius must be half that or 3.