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3 years ago

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Drag each tile to the correct box consider the given functions f,g and h place the tiles in order from least to greatest accordi

ng to the average rate of change of the functions over the interval 0,3 h(x)=x^2+x-6

1 answer:

Alja [10]3 years ago

3 0

Answer:

Step-by-step explanation:

By definition, the average rate of change of a function f over an interval [a,b] is given by

$\dfrac{f(b)-f(a)}{b-a}$

compute the quantity

$\dfrac{f(3)-f(0)}{3}$

for all the three function

Average rate of change of f:

We will simply use the table to check the values for f(3) and f(0):

$\dfrac{f(3)-f(0)}{3}=\dfrac{10-1}{3} = 3$

Average rate of change of g:

We will use the graph to to check the values for g(3) and g(0):

$\dfrac{g(3)-g(0)}{3}=\dfrac{8-1}{3} = \dfrac{7}{3}$

Average rate of change of h:

We can plug the values in the equation to get h(3) and h(0):

$h(3)=3^2+3-6=9+3-6=6,\quad h(0)=0^2+0-6=-6$

And so the average rate of change is

$\dfrac{h(3)-h(0)}{3}=\dfrac{6-(-6)}{3} = 4$

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Answer:

400 miles per hour

Step-by-step explanation:

2.000 miles : 5 hours =400 miles per hour

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3 years ago

Is 2/3 equivalent to 1/3 if it isn't then which is bigger plz help and will give a thanks

lina2011 [118]

Compare the enumerators because they have the same denominator. 2 is large than 1 so 2/3 is larger than 1/3

Hope this helps!

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The perimeter of a rectangle is given by P equals 2 l plus 2 w. Find the width of a rectangle whose length is 35 and perimeter i

maks197457 [2]

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4 years ago

The ages of the Oscar-winners for best actor and actress for the years 1970 through 1990 are given below: Women: 34, 34,26,37,42

Artemon [7]

Answer:

See explanation below.

Step-by-step explanation:

Numerical way

We can calculate the mean and the standard deviation from a sample with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s= \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

We have the following dataset for women: 34,34,26,37,42,41,35,31,41,33,30,74,33,49,38,61,21,41,26,80,72

And the mean and deviation are:

$\bar X_F = 41.857$

$s_F = 16.399$

We can calculate the median ordering the data like this:

21,26,26,30,31,33,33,34,34,35,37,38,41,41,41,42,49,61,72,74,80

And the median would be on the 11 position of the data ordered, for this case is:

$median_F = 37$

$Minimum_F = 21 , Maximum_F = 80$

And the range is given by: $Range_F = 80-21=59$

We can also calculate the coefficient of variation given by:

$\hat{CV} =\frac{s}{\bar X} = \frac{16.399}{41.857}=0.392$

We have the following dataset for men:

43, 40,48,48,56,38,60,32,40,42,37,76,39,55,45,35,61,33,51,32,42

And the mean and deviation are:

$\bar X_M = 45.381$

$s_M = 11.218$

We can calculate the median ordering the data like this:

32, 32,33,35,37,38,39,40,40,42,42,43,45,48,48,51,55,56,60,61,76

And the median would be on the 11 position of the data ordered, for this case is:

$median_M = 42$

$Minimum_M = 32 , Maximum_F = 76$

And the range is given by: $Range_M = 76-32=44$

We can also calculate the coefficient of variation given by:

$\hat{CV} =\frac{s}{\bar X} = \frac{11.218}{45.381}=0.247$

We se that the mean for the male groups is higher than the mean for female group. The deviation is higher for the female group comapred to the male group. We have more variation for the female group as we can see on the range and the coeffcient of variation.

Graph

We can see the histograms for each group on the figures attached.

As we can see the histogram for males is skewed to the right with the median lower than the mean.

By the other hand the histogram for the female group seems to be skewed to the right also but with missing values on the interval 50-60, for this reason we have more variation compared to the male group.

7 0

3 years ago