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ella [17]
3 years ago
13

Please give me the ansewer to this question 3/4^3

Mathematics
2 answers:
n200080 [17]3 years ago
7 0

Answer:

2.25

Step-by-step explanation:

galben [10]3 years ago
3 0

♡ The Question ♡

-Answer --> 3/4^3

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ The Answer ♡

Fraction --> 27/64

Decimal --> 0.421875

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ The Explanation/Step-By-Step ♡

(3/4)^3

Apply Exponent Rule! --> (a/b)^c = a^c/b^c

(3/4)^3 = 3^3/4^3

3^3 = 27

= 27/4^3

4^3 = 64

= 27/64

27/64 = 0.421875

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ Tips ♡

-No tips provided!

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Answer:

Step-by-step explanation:

a = -4/3

d= -1 +4/3 =1/3

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\frac{-4}{3}+(n-1)*\frac{1}{3}=\frac{13}{3}\\\\(n-1)*\frac{1}{3}=\frac{13}{3}-\frac{-4}{3}\\\\(n-1)*\frac{1}{3}=\frac{13+4}{3}\\\\(n-1)*\frac{1}{3}=\frac{17}{3}\\\\n-1=\frac{17}{3}*\frac{3}{1}\\\\n-1=17\\\\n=17+1=18

Middle terms are 9the term and 10th term

t_{9}=\frac{-4}{3}+8*\frac{1}{3}=\frac{-4}{3}+\frac{8}{3}=\frac{4}{3}\\\\t_{10}=\frac{-4}{3}+9*\frac{1}{3}=\frac{-4}{3}+\frac{9}{3}=\frac{5}{3}\\\\ t_{9}+t_{10}=\frac{4}{3}+\frac{5}{3}=\frac{9}{3}=3\\\\t_{9}+t_{10}=3

3 0
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7th grade math!
pishuonlain [190]

Answer:

I just learned about this, and if its wrong i am so so sorry

Step-by-step explanation:

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How to solve this problem​
nevsk [136]

Let C be the center of the circle. The measure of arc VSU is 2+114x, so the measure of the minor arc VU is 360-(2+114x)=358-114x. The central angle VCU also has measure 358-114x.

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UT is tangent to the circle, so CU is perpendicular to UT. Angles CUV and VUT are complementary, so

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