2 years ago

I can't manage. Can you help? Ty :)

Mathematics

1 answer:

grigory [225]2 years ago

5 0

first question is true and second question is 6cm

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A wheel initially has an angular velocity of 18 rad/s, but it is slowing at a constant rate of 2 rad/s 2 . By the time it stops,

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Answer:13 revolution

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Given data

Wheel initial angular velocity $\left ( \omega \right )$ =18 rad/s

Contant angular deaaceleration $\left ( \alpha \right )$ =2 $rad/s^2$

Time required to stop wheel completely=t sec

$\omega =\omega_0 + \aplha t$

0 =18 + $\left ( -2\right )t$

t=9 sec

Therefore angle turn in 9 sec

$\theta$ = $\omega_{0} t$ + $\frac{1}{2}$ $\left ( \alpha\right )t^{2}$

$\theta$ = $18\times 9$ + $\frac{1}{2}$ $\left ( -2\right )\left ( 9\right )^2$

$\theta$ =81rad

therefore no of turns(n) = $\frac{81}{2\times \pi}$

n=12.889 $\approx$ 13 revolution

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I can't manage. Can you help? Ty :)​

I can't manage. Can you help? Ty :)