What is an equation of the line that passes through the point (−6,−1) and is perpendicular to the line 6x−y=7?
1 answer:
Answer:
y=-1/6x-2
Step-by-step explanation:
Lets find the slope of the given line
6x-7=y,m=6
The slope of the perpendicular line would be=-1/6
Using the point-slope form y-y1=m(x-x1)
y--1=-1/6(x--6)
y+1=-1/6(x+6)
6y+6=-x-6
6y=-x-6-6
6y=-x-12
y=-1/6x-2
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