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Rus_ich [418]
3 years ago
12

If / (x) = 2(x)2 +5/(x+2), complete the following statement: f2) = _

Mathematics
1 answer:
kogti [31]3 years ago
7 0

Answer:

18

Step-by-step explanation:

f(x) = 2(x)^2 +5 sqrt(x+2)

Let x =2

f(2) =2(2)^2 +5 sqrt(2+2)

    = 2 *4 + 5 (sqrt(4))

    = 8 + 5*2

    = 8 + 10

   = 18

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In a game the player wins if he rolls a 6 on a number cube. If the number cube is rolled 18 times, then what is a reasonable pre
Mamont248 [21]
On a cube, you have 6 faces, therefore you have 1 chance to get 6 and 5 chances not to get 6.

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If you roll the cube 18 times, the prediction of unsuccessful rolls will be:
18 × 0.8333 = 15

Therefore, you expect to have 15 unsuccessful rolls over 18 total rolls.
7 0
3 years ago
Please someone answer quick I need this for tomorrow for school and I'm not done pls tell me the right answer thanks
nikklg [1K]

answer to a) 18,36,,54

answer to b) 30,60,90

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4 years ago
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The lines given by the equations y=4x and y=0.25x are
d1i1m1o1n [39]

They are not parallel because the slopes are different (slope of 4 and slope of 0.25)

Neither are they perpendicular. If they were then m1*m2  ( the product of their slopes) would be -1 ). The product of these slopes = 4*0.25 = 1)

So choice  A is the correct one.


6 0
3 years ago
The graph below could be the graph of which exponential function?
MrMuchimi

Your answer is B F(x) * (0.5)^x

7 0
3 years ago
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If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°
Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = c^{2} = a^{2} + b^{2}

a = 7 and b = 11

a^{2} = 49

b^{2} = 121

Plugging in the values, we will get:

c^{2} = 49 + 121

c^{2} = 170

c = \sqrt{170}

To calculate the unknown angle B, we can use law of sine.

Law of sine = \frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

So,

\frac{c}{sinC} = \frac{b}{sinB}

\frac{\sqrt{170} }{sin90} =  \frac{11}{sinB}

Sin90 = 1

sinB = \frac{11}{\sqrt{170} }

B = sin^{-1} (\frac{11}{\sqrt{170} })

B = 57.5°

8 0
3 years ago
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