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2 years ago

A rectangle measures 2 1/2 meters by 1 3/4 meters. What is its area?

Mathematics

1 answer:

REY [17]2 years ago

3 0

Answer:

4 3/8

Step-by-step explanation:

1. We can use the formula

Area = L (length) x W (width)

2. The area is unknown so we can substitute it for a

The length and width are both known, so we can plug them in.

a= 2 1/2 x 1 3/4

3. Solve by multiplying

a=4 3/8

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What is more accurate, mean or average? Explain why.

Airida [17]

It can be viewed different to what is more accurate depending on the relation of this question to another.

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2 years ago

Y= |x−3| + |x+2| − |x−5|, if x>5 I need to know what y equals.

olganol [36]

Answer:

$y \ge9$

Step-by-step explanation:

The given function is

$y = |x - 3| + |x + 2| - |x - 5|$

By the triangle inequality property,

$|x + y| \leqslant |x| + |y|$

and the alternate triangle inequality property;

$|x - y| \geqslant |x| - |y|$

We apply this property to get:

$y \geqslant |x | - |3| + |x | + |2| -( |x | - |5| )$

Expand parenthesis to get:

$y \geqslant |x | - |3| + |x | + |2| - |x | + |5|$

Simplify to get:

$y \geqslant |x | - 3+ |x | + 2- |x | + 5$

Group similar terms to get:

$y \geqslant |x | + |x | - |x | - 3 + 2+ 5$

$y \geqslant |x | + 4$

When x>5,

$y \geqslant |5 | + 4$

That's;

$y \geqslant 5 + 4 \\ y \geqslant 9$

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2 years ago

Write and Solve a real world problem in which the part of a whole results in a number greater than the whole itself

Agata [3.3K]

That's not physically possible, but this is what I got:

Draegast had gained 2/3 times as many subscribers as he had before overnight. He had 20/36 as many subs as Pewds. He has 40,000,000 subs.

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2 years ago

Solve the equations by elimination. -7x-8y=9 -4x+9y=-22

Sergeeva-Olga [200]

Solve for x in -7x - 8y = 9

x = -9 + 8y/7

Substitute x = -9 + 8y/7 into -4x + 9y = -22

4(9 + 8y)/7 + 9y = -22

Solve for y in 4(9 + 8y)/7 + 9y = -22

y = -2

Substitute y = -2 into x = -9 + 8y/7

x = 1

Thus,

x = 1

y = -2

4 0

3 years ago

In 2000, 31% of U.S adults viewed a college education essential for success. For the period 2000-2010, the percentage viewing a

Fynjy0 [20]

$\bf \begin{array}{ccrllll}
term&year&\%\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
1&2000&31\\
2&2001&31+2.4\\
3&2002&(31+2.4)+2.4\\
4&2003&(31+2.4+2.4)+2.4\\
...&...&...\\
\boxed{?}&\boxed{?}&67
\end{array}
\\ \\
the\ n^{th}\textit{ term of an arithmetic sequence, will be}

$ $\bf a_n=a_1+(n-1)d\qquad 
\begin{cases}
a_1=\textit{first term}\to 31\\
d=\textit{common difference}\to 2.4\\
n=the\ n^{th}\ term
\end{cases}
\\ \quad \\
thus
\\ \quad \\
a_n=a_1+(n-1)d\implies 67=31+(n-1)2.4$

solve for "n"

the value of the "n"th term is 67, we know that much,
so, "n" will give you how many years it took to be 67

6 0

3 years ago