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Crazy boy [7]
3 years ago
15

In need of help plz Find the ∠VXW and ∠XVW

Mathematics
1 answer:
My name is Ann [436]3 years ago
4 0

Answer:

∠VXW = 57°

∠XVW = 56°

Step-by-step explanation:

Firstly, we need to remember the sum of a triangle's angle ALWAYS equals 180°.

Next, we see that two angles of △XYZ are given to us; 58° and 65°. Adding these two numbers would give us 123°. Now we need to subtract 123 from 180  to find the ∠YXZ; 180° - 123° = 57°.

Once we have this number, we need to remember a straight line also measures 180°. Line YW is important to find our answer, but first we need to find the answer to ∠WXZ. Since ∠YXZ and ∠WXZ come together and create the line YW, we can easily find the answer to ∠WXZ by subtracting ∠YXZ with 180; 180° - 57° = 123°

Now we need to find ∠VXW keeping the previous things I mentioned in mind; 180° - 123° = 57°. This is the answer to our first angle ∠VXW.

Since a triangle's angles always equal to 180° and we have the answer to two angles in △XVW, all we need to do is add then subtract;

67° + 57° = 124°

180° - 124° = 56°

And that is your answer!

∠VXW = 57°

∠XVW = 56°

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Answer:

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Hope this helps

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Consider 4 flips of an unfair coin where probability of heads is 0.40. Consider all tosses independent of each other. (a) Compar
romanna [79]

Answer:

a) 0.0256 = 2.56% probability of 4 heads.

0.1296 = 12.96% probability of 4 tails.

b) The probability is 0.0576 = 5.76%.

c) 6 outcomes given 2 heads in 4 tosses. 0.3456 = 34.56% probability of 2 heads in 4 tosses

Step-by-step explanation:

For each throw, we have these following probabilities:

0.4 = 40% probability of heads.

0.6 = 60% probability of tails.

(a) Compare the probability of 4 heads in 4 tosses and 4 tails in 4 tosses.

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4 throws, each with 0.4 probability of heads. So

(0.4)^4 = 0.0256

0.0256 = 2.56% probability of 4 heads.

4 tails:

4 throws, each with 0.6 probability of tails. So

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(b) Determine the probability of H T H T in 4 tosses.

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p = 0.4*0.6*0.4*0.6 = 0.0576

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(c) Determine the number of outcomes that give us 2 heads in 4 tosses in any order. What is the probability of 2 heads in 4 tosses (use (b) and the number of outcomes)

Number of outcomes:

The possible outcomes are:

H - H - T - T

H - T - H - T

H - T - T - H

T - H - H - T

T - H - T - H

T - T - H - H

6 outcomes given 2 heads in 4 tosses.

Each with probability 0.0576, as found in b)

6*0.0576 = 0.3456

0.3456 = 34.56% probability of 2 heads in 4 tosses

8 0
2 years ago
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