There are 18 coins total in her bag:
7+3+8=18coins
3 of the 18 coins are dimes, so the odds of first drawing a dime are 3/18
P(dime)=3/18
Since the nickel was taken out and not replaced, there are now 17 coins in her purse.
18-1=17coins
8 of the 17 remaining coins are nickels, so the odds of drawing a nickel are 8/17.
P(nickel)=8/17
Now we multiply the two probabilities by eachother to find out the odds of both occurring...
P(dime)*P(nickel)=
3/18*8/17=24/306=8/103=0.078=8%
The probability of grabbing a dime and then a nickel are 8/103 or 0.078 or an 8% chance, whichever way you'd prefer to write it.
<span>1067/10000 is the simplest version
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Greetings! Hope this helps!
Answer
3 + 2h = 7
-3 -3
2h = 4
/2 /2
h = 2
Have a good day!
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A brainliest would help tons! :D
Answer: Hello mate!
The partition of a set is defined as a partition of the set into a nonempty subset, where the set itself is a subset of himself, then the set is a partition of himself.
a) in this we have a set of two objects; A = (1,2) the partitions of this set are: (∅), (1), (2) and (1,2). Where (∅) is the null set.
b) Now we have a set of three objects; B = (a,b,c) the partitions of this set are: (∅), (a), (b), (c), (a,b), (a,c), (b,c), (a,b,c)
