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3 years ago

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Given that events A and B are independent with P(A)=0.5 and P(B)=0.15, determine the value of P(A∣B), rounding to the nearest th

ousandth, if necessary.

1 answer:

g100num [7]3 years ago

8 0

Owner is very happy and very happy to join us to help us

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The table represents an exponential function.

kkurt [141]

Answer:

b=2/3

Step-by-step explanation:

The table is given as:

$\left|\begin{array}{c|c}x&y\\--&--\\1&9\\2&6\\3&4\\4&\dfrac83\\\\5&\dfrac{16}{9}\end{array}\right|$

The exponential function is given in the form

$y= a (b)^{x}$

where a is the initial value and b is the multiplicative rate of change

When x=1, y=9, we have:

$9= a (b)^{1}$

When x=3, y=4, we have:

$4= a (b)^{3}$

Dividing the two equations:

$\dfrac{a (b)^{3}}{a (b)^{1}} =\dfrac{4}{9} \\b^2=\dfrac{4}{9}\\b=\sqrt{\dfrac{4}{9}} \\b=\dfrac{2}{3}$

The multiplicative rate of change, b is 2/3.

5 0

3 years ago

James went out for. a long walk . he walked 3/4 mile and then sat down to take rest. then walked 1/8 of a mile how far did he wa

Karo-lina-s [1.5K]

change 3/4 to 6/8 and add 6/8 and 1/8 to get 7/8

he walked 7/8 miles in total :)

6 0

2 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the

yarga [219]

Answer:

$(x-5)^2+(y-2)^2=9\\$

Step-by-step explanation:

So, you basically want the equation of the circle.

Given:

Center(C): $C(5, 2)$

$r=3$

The equation of circle is:

$(x-h)^2+(y-k)^2=r^2\\$

Where, $(h, k)$ represents the center point and $r$ is the radius of the circle.

Plotting the values in the equation:

$(x-5)^2+(y-2)^2=3^2\\$

$(x-5)^2+(y-2)^2=9\\$

This is the equation of the circle of center (5, 2) and radius 3.

6 0

3 years ago

What is the factored form of the expression? 16. d 2 + 18d + 81 (1 point) (d + 9)(d – 9) (d + 9) 2 (d – 81)(d – 1) (d – 9) 2

jarptica [38.1K]

Since a and c in this equation are perfect squares, you know that the value of the factored form is going to be the (sqrt of a*d added to the sqrt of 81)^2, making(d+9)^2

3 0

3 years ago

Divide f(x) by d(x), and write a summary statement in the form indicated.

Mandarinka [93]

Answer:

The correct option is B) $f(x) =(x^2+1)(x^2+4x+5)$

Step-by-step explanation:

Consider the provided function.

$f(x) = x^4 + 4x^3 + 6x^2 + 4x + 5$ and $d(x) = x^2+1$

We need to divide f(x) by d(x)

As we know: Dividend = Divisor × Quotient + Remainder

In the above function f(x) is dividend and divisor is d(x)

Divide the leading term of the dividend by the leading term of the divisor: $\frac{x^4}{x^2}=x^2$

Write the calculated result in upper part of the table.

Multiply it by the divisor: $x^2(x^2+1)=x^4+x^2$

Now Subtract the dividend from the obtained result:

$(x^4 + 4x^3 + 6x^2 + 4x + 5)-(x^4-x^2)=4x^3+5x^2+4x+5$

Again divide the leading term of the obtained remainder by the leading term of the divisor: $\frac{4x^3}{x^2}=4x$

Write the calculated result in upper part of the table.

Multiply it by the divisor: $4x(x^2+1)=4x^3+4x$

Subtract the dividend:

$(4x^3+5x^2+4x+5)-(4x^3+4x)=5x^2+5$

Divide the leading term of the obtained remainder by the leading term of the divisor: $\frac{5x^2}{x^2}=5$

Multiply it by the divisor: $5(x^2+1)=5x^2+5$

Subtract the dividend:

$(5x^2+5)-(5x^2+5)=0$

Therefore,

Dividend = $x^4 + 4x^3 + 6x^2 + 4x + 5$

Divisor = $x^2+1$

Quotient = $x^2+4x+5$

Remainder = 0

Dividend = Divisor × Quotient + Remainder

$f(x) = (x^2+1)(x^2+4x+5)$

Hence, the correct option is B) $f(x) =(x^2+1)(x^2+4x+5)$

3 0

3 years ago