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Alekssandra [29.7K]
3 years ago
8

Many Australian highways have a speed of 110 kilometers per hour. Convert this to miles per hour

Mathematics
1 answer:
grin007 [14]3 years ago
4 0

Answer:

Step-by-step explanation:

It's a little over 60 mph

110 km = 110 km * 0.6 miles / km = 66 miles

110 km/hour = 66 miles / hour

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What value cannot be determined from the box and whisker plot
spin [16.1K]

Answer:

D mean

Step-by-step explanation:

Box and whiskers is based on five points, data values are not marked so mean can not be computed

3 0
3 years ago
Read 2 more answers
Select the equations in point-slope form for the line below (CHOOSE TWO EQUATIONS)
Crank

Answer:

y-3=\frac{4}{3}\left(x-1\right) and y+1=\frac{4}{3}\left(x+2\right)

Step-by-step explanation:

Here is how I found out the answers, i graphed them on Desmos:

y+1=\frac{4}{3}\left(x+2\right)=solid red line

y-3=\frac{4}{3}\left(x-1\right) = dotted black line

Hope this helps! Brainliest would be much appreciated! Have a great day! :)

3 0
2 years ago
Please help!
romanna [79]
In this item, we are given with the amounts of both the flour and sugar. 

Part A:
First, we determine the total amount of recipes needed for the batch.
    total amount = (4 1/5 cup) + (2 3/7 cup)
     total amount = 232/35 cup

To determine the total amount of sugar needed for 4/9 of the recipe, we multiply the given amount of sugar by 4/9. That is,
            amount of sugar = (4/9)(2 3/7) 
      <em>      amount of sugar = 68/63 cups of sugar</em>

Part B: To determine the amount of flour needed is 3 times the given amount for each batch.

      amount of flour = (3)(4 1/5 cups of flour)
    <em> amount of flour = 63/5 cups or 12.6 cups of flour</em>

4 0
3 years ago
Prove that if a and b are integers, then a^2-4b egal or non-egal 2
Lera25 [3.4K]

Answer:

tex]a^2 - 4b \neq 2[/tex]

Step-by-step explanation:

We are given that a and b are integers, then we need to show that a^2 - 4b \neq 2

Let  a^2 - 4b = 2

If a is an even integer, then it can be written as a = 2c, then,

a^2 - 4b = 2\\(2c)^2 - 4b =2\\4(c^2 -b) = 2\\(c^2 -b) =\frac{1}{2}

RHS is a fraction but LHS can never be a fraction, thus it is impossible.

If a is an odd integer, then it can be written as a = 2c+1, then,

a^2 - 4b = 2\\(2c+1)^2 - 4b =2\\4(c^2+c-b) = 2\\(c^2+c-b) =\frac{1}{4}

RHS is a fraction but LHS can never be a fraction, thus it is impossible.

Thus, our assumption was wrong and a^2 - 4b \neq 2.

7 0
3 years ago
3. At a bargain store, Tanya bought 4 items that each cost the same amount. Tony bought 5 items that each cost the same amount,
Murljashka [212]

Tanya spent $9.00 on each item; Tony spent $6.75 on each of his items.

5 0
4 years ago
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