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defon
3 years ago
6

What's the answer to 2x-4y=20? Solve the literal equation for y.

Mathematics
1 answer:
Yakvenalex [24]3 years ago
3 0
If I did the work correctly, your answer should be 1/2x -10=y
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I would like to see the process to this question and the answer to it: <br> 2(cos 80+ i sin 80)
Bezzdna [24]
<span>(-0.220774488 - 1.98777731 i) So that should be your answer
And i put that into my calculator so i don't know how to get the steps i really sorry i wish i knew

</span>
7 0
3 years ago
GEOMETRY. I will give brainliest
lubasha [3.4K]

Given:

A figure of a circle. A secant and tangent of the given circle.

To find:

The correct equation.

Solution:

According the intersecting tangent secant theorem, the square of tangent is equal to the property of external segment of secant and the measure of the secant.

Using intersecting tangent secant theorem, we get

6^2=x(x+5)

It can be written as

x(x+5)=6^2

The required equation is x(x+5)=6^2.

Therefore, the correct option is B.

8 0
3 years ago
An event management company purchases a new van. The value of the van, x years after the purchase, is shown in the table. here i
Vlad1618 [11]

Answer:

D

Step-by-step explanation:

A is not right as we don't know the formula used so we cant say the x intercept

B is not right as the function is not liner

C The function is not liner

That leaves D!

hope this helps!

4 0
4 years ago
The right arrow symbol used to show the transition from a point to its image after a transformation is not contained within the
Bumek [7]

Given:

Vertices of triangle ABC are A (1,4), B(3,−2) and C(4,2).

Triangle ABC reflected over the x-axis to get the triangle A'B'C'.

To find:

The coordinates of the image A'B'C'.

Solution:

If a figure reflected over the x-axis, then rule of transformation is

(x,y)\to (x,-y)

Now, using this rule, we get

A(1,4)\to A'(1,-4)

B(3,-2)\to B'(3,2)

C(4,2)\to C'(4,-2)

Therefore, the coordinates of the image  A'B'C' after a reflection over the x-axis are A'(1,-4), B'(3,2) and C'(4,-2).

7 0
4 years ago
Using the completing-the-square method, find the vertex of the function f(x) =- 3x2 + 6x − 2 and indicate whether it is a minimu
svp [43]
F(x) = -3x² + 6x - 2
First, we make the coefficient of x² equal to 1
f(x) = -3(x² + 2x - 2/3)

Now, we must make the form a² + 2ab + b²
b = 2x/2x
b = 1

f(x) = -3(x² + 2x + 1² - 1² - 2/3)
f(x) = -3(x² + 2x + 1 - 5/3)
f(x) = -3(x + 1)² - 5

The vertex is (-1 , -5)
And this is the maximum point because the coefficient of the squared term is negative.
6 0
3 years ago
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