<span>(-0.220774488 - 1.98777731 i) So that should be your answer
And i put that into my calculator so i don't know how to get the steps i really sorry i wish i knew
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Given:
A figure of a circle. A secant and tangent of the given circle.
To find:
The correct equation.
Solution:
According the intersecting tangent secant theorem, the square of tangent is equal to the property of external segment of secant and the measure of the secant.
Using intersecting tangent secant theorem, we get

It can be written as

The required equation is
.
Therefore, the correct option is B.
Answer:
D
Step-by-step explanation:
A is not right as we don't know the formula used so we cant say the x intercept
B is not right as the function is not liner
C The function is not liner
That leaves D!
hope this helps!
Given:
Vertices of triangle ABC are A (1,4), B(3,−2) and C(4,2).
Triangle ABC reflected over the x-axis to get the triangle A'B'C'.
To find:
The coordinates of the image A'B'C'.
Solution:
If a figure reflected over the x-axis, then rule of transformation is

Now, using this rule, we get



Therefore, the coordinates of the image A'B'C' after a reflection over the x-axis are A'(1,-4), B'(3,2) and C'(4,-2).
F(x) = -3x² + 6x - 2
First, we make the coefficient of x² equal to 1
f(x) = -3(x² + 2x - 2/3)
Now, we must make the form a² + 2ab + b²
b = 2x/2x
b = 1
f(x) = -3(x² + 2x + 1² - 1² - 2/3)
f(x) = -3(x² + 2x + 1 - 5/3)
f(x) = -3(x + 1)² - 5
The vertex is (-1 , -5)
And this is the maximum point because the coefficient of the squared term is negative.