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3 years ago

Find the area of the figure.

Mathematics

1 answer:

Sindrei [870]3 years ago

8 0

Answer:

should be 41

Step-by-step explanation:

Length x width = area

3x3=9

4x8=32

add 32 and 9 and u get 41

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Number of Tickets Total Cost 1 $2.50 2 ? 3 $7.50 4 ? 5 $12.50 6 $15.00 7 $17.50 Assuming that the cost of tickets follows the sa

Gala2k [10]

2= 5.50 4= 10.50 here is your answer

7 0

3 years ago

A dozen plain hats cost 3.60,what is the unit rate of a hat?

deff fn [24]

I think the answer should be 12.

7 0

3 years ago

Read 2 more answers

Kyla used 550 grams of wool to knit a sweater, a hat, and a scarf. For the hat she used 5 times less wool than the sweater and 5

Brrunno [24]

This is the concept of algebra, to calculate the proportion of wool in each item we proceed as follows;
Let the amount of wool used for hat be x
amount of wool in sweater will be 5x
the amount of wool used in scarf will be x-5
therefore the total amount of wool will be:
x+5x+(x-5)=550
x+5x+x-5=550
7x-5=550
7x=550+5
7x=555
hence;
x=555/7
x=79
the amount used in hat x=79g
amount used in sweater 5x=395g
amount used in scarf=79-5=74g

5 0

3 years ago

Please help!!!!!!!!!!! ASAPPPPPPPPP

Zanzabum

When you match the pattern of (x+y)⁴ to (a+b)ⁿ, you see that a=x, n=4. Then the first term aⁿ can be found by substituting these values for "a" and "n":

... x⁴

7 0

3 years ago

Let f(x)=x^2f ( x ) = x 2. Find the Riemann sum for ff on the interval [0,2][ 0 , 2 ], using 4 subintervals of equal width and t

sladkih [1.3K]

Answer:

$A_L=1.75$

Step-by-step explanation:

We are given:

$f(x)=x^2$

$interval = [a,b] = [0,2]$

Since $n = 4$ ⇒ $\Delta x = \frac{b-a}{n} = \frac{2-0}{4}=\frac{1}{2}$

Riemann sum is area under the function given. And it is asked to find Riemann sum for the left endpoint.

$A_L= \sum\limits^{n}_{i=1}\Delta xf(x_i) = \frac{1}{2}(0^2+(\frac{1}{2})^2+1^2+(\frac{3}{2})^2)=\frac{7}{4}=1.75$

Note:

If it will be asked to find right endpoint too,

$A_R=\sum\limits^{n}_{i=1}\Delta xf(x_i) =\frac{1}{2}((\frac{1}{2})^2+1^2+(\frac{3}{2})^2+2^2)=\frac{15}{4}=3.75$

The average of left and right endpoint Riemann sums will give approximate result of the area under $f(x)=x^2$ and it can be compared with the result of integral of the same function in the interval given.

So, $(A_R+A_L)/2 = (1.75+3.75)/2=2.25$

$\int^2_0x^2dx=x^3/3|^2_0=8/3=2.67$

Result are close but not same, since one is approximate and one is exact; however, by increasing sample rates (subintervals), closer result to the exact value can be found.

3 0

3 years ago