Given the functions
(a) f(x) = x³ + 5x² + x
(b) f(x) = x² + x
(c) f(x) = -x
Function (a)
f(-x) = (-x)³ + 5(-x)² + (-x)
= -x³ + 5x² - x
= -(x³ - 5x² + x)
The function is neither even nor odd.
Function (b)
f(-x) = (-x)² + (-x)
= -(-x² + x)
The function is neither even nor odd.
Function (c)
f(-x) = -(-x)
= x
= -f(x)
Because f(-x) = -f(x) the function is odd.
Answer: f(x) = -x is an odd function.
You would use PEMDAS
But since any number divided by 1 is the number by which it is divided by then you can eliminate that. Now your problem looks like this:
8✖️4➕9✖️56➕57
Since there are no parentheses or exponents then you would multiply.
8✖️4= 32
32➕9✖️56➕57
Then multiply the other multiplication problem.
9✖️56= 504
32➕504➕57
Now you can add all of the numbers together
32➕504=536
536➕57=593
Your answer is 593
Hope this helps! :3
Good luck to Jonathan. I hope he gets his sport set soon.
1) -10,-2
2) -13,-3
3) 2,2
4) -5,3
