The OS shell allows access to the operating system services
Answer:
x = int(input("What grade are you in? "))
if (x == 9):
print ("Freshman")
elif (x == 10):
print("Sophomore")
elif (x == 11):
print ("Junior")
elif (x == 12):
print("Senior")
else:
print ("Not in High School")
Explanation:
Answer:
class Main {
public static void printPattern( int count, int... arr) {
for (int i : arr) {
for(int j=0; j<count; j++)
System.out.printf("%d ", i);
System.out.println();
}
System.out.println("------------------");
}
public static void main(String args[]) {
printPattern(4, 1,2,4);
printPattern(4, 2,3,4);
printPattern(5, 5,4,3);
}
}
Explanation:
Above is a compact implementation.
Answer:
1 14 3
Explanation:
If that code fragment is put under a main() function and then it will yield the above output. According to the function something(), only changes in value second parameter will be reflected and first will be unchanged because second is passed by reference and the first one is passed as value so only address of 's' is passed, so, only its value is changed and the rest are same.
Answer:
The program to this question as follows:
Program:
def lettersOnly(s): #defining method lettersOnly
val="" #defining string variable that return value
for i in s: #defining loop to calculate value
if(i.isalpha()): #check condition that value is string
val=val+ i #add value
return val #return value
print(lettersOnly("data3base_ro1c3k5s")) #call method and print value
Output:
databaserocks
Explanation:
In the above python code, a method lettersOnly is declared that accepts a string variable "s" in its parameter. Inside the method, a string variable "val", and loop is declared, in which the "val" variable holds method return value.
- In the loop and if block is used that uses "isalpha" string method, which checks the check alphabetic character in the given value. if this is true it will calculate all value in "val" variable and return its value.
- At the last, the print method is used, which calls the lettersOnly method and prints its return value.