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zhenek [66]
3 years ago
9

What variation of a dictionary attack involves a dictionary attack combined with a brute force attack, and will slightly alter d

ictionary words by adding numbers to the end of the password, spelling words backward, slightly misspelling words, or including special characters?
a. brute force
b. hash replay
c. network replay
d. hybrid
Computers and Technology
1 answer:
Galina-37 [17]3 years ago
6 0

Answer:

D) Hybrid Attack

Explanation:

This type of  attack is a blend of both a dictionary and brute force attack. The meaning of this is, while a dictionary attack method would capture a wordlist of passwords, the brute-force attack would be applied to each of  password captured.

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scheduling is approximated by predicting the next CPU burst with an exponential average of the measured lengths of previous CPU
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SJF scheduling is approximated by predicting the next CPU burst with an exponential average of the measured lengths of previous CPU bursts.

<h3>What is SJF in operating system?</h3>

SJF is a term that connote Shortest Job First. It is said to be a type of CPU scheduling whose algorithm is linked with each as it is said to process the length of the next CPU burst.

Note that for one to be able to know the time for the next CPU burst to take place, one need to take the SJF into consideration as that is its function.

Hence, SJF scheduling is approximated by predicting the next CPU burst with an exponential average of the measured lengths of previous CPU bursts.

See options below

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Which input value causes the loop body to execute a 2nd time, thus outputting "In loop" again? { String s = "Go"; while ((!s.equ
Ksenya-84 [330]

Answer:

a) "Quit"  

c) "Q only

Explanation:

Given

<em>String s = "Go"; </em>

<em>while ((!s.equals("q"))&& (!s.equals("")))  {</em>

<em>System.out.println("In loop"); </em>

<em>s = scnr.next();</em>

<em>}</em>

<em />

Required

What input causes another execution

Analyzing the while condition

<em>while ((!s.equals("q"))&& (!s.equals("")))  </em>

<em />

This can be split into:

<em>!s.equals("q")) && (!s.equals(""))</em>

<em />

Meaning

When s is not equal to "q" and when s is not an empty string

<em />

In other words,

the loop will be executed when user input is not "q" and user input is not empty.

So, from the list of given options: The loop both will be executed when:

a) Input is "Quit"

c) Input is Q only

<em>Input of q will terminate the loop, hence b and d are incorrect</em>

<em />

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