the answer is it is proportional
Step-by-step explanation:
sin4Acosec2A+cos4Asec2A=sin2Asin4A+cos2Acos4A=sin2A+cos2A=1
Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
Sorry, a bit late but i took it and it was A.
If Adam has 16.45 kg of flour and he uses 6.4 kg to make hot cross buns, then he has left
16.45 - 6.4 = 10.05 kg of flour.
If Adam wants to use the remaining flour to make 15 batches of scones, then each batch of scones requires
10.05 : 15 = 0.67 kg of flour.
Answer: each batch of scones requires 0.67 kg of flour.
