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3 years ago

Find the value of x. PICTURE BELOW \/

Mathematics

1 answer:

Sedaia [141]3 years ago

3 0

Answer:

x = 139

Step-by-step explanation:

This figure is a quadrilateral. The angles add up to 360 degrees

47+82+92+x = 360

Combine like terms

221+x =360

Subtract 221 from each side

221+x-221 = 360-221

x = 139

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The variable z is directly proportional to x, and inversely proportional to y. when x is 16 and y is 17, z has the value 11.2941

Tresset [83]

Lets suppose k is the constant of proportionality.

z = k * x / y

when x is 16 and y is 17, z has the value 11.294117647059

11.294117647059 = k * 16/17

Multiplying 17 on both sides

11.294117647059 * 17 = k * 16

192 = k * 16

Dividing 16 on both sides

192/16 = k

k = 12

Now when x= 22, and y= 26

z = k * x/y

z = 12 * 22 / 26

z = 10.1538461538 : Answer

Hope it will help :)

8 0

3 years ago

Kim bought 24 apples at the market. She put 4 apples into each of 4 drawers in her kitchen. She gave the rest of them to her fri

ella [17]

To find out the answer, you first need to know how many apples you have. So since you put 4 apples in 4 drawers, we just multiply 4×4 to get our answer so, 4×4= 16, So you have 16 apples. To find out how many you gave your friend, you just subtract 24 - 16 = 8, So your friend got 8 apples.

7 0

4 years ago

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If x - 5y = 6, what is the value of y when X= -4? A:-2 B-2/5 C:2/5 D:2

zysi [14]

Answer:

I think the answer is D. 2

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3 years ago

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The coordinate grid shows the plot of four equations.

Rom4ik [11]

Answer:

Your answer would be A and B

Step-by-step explanation:

Simply look for the coordinates on the graph and look for the name of the lines that intersect there.

5 0

3 years ago

Help me on this please

zalisa [80]

Answer:

1. (x, y) → (x + 3, y - 2)

Vertices of the image

a) (-2, - 3)

b) (-2, 3)

c) (2, 2)

2. (x, y) → (x - 3, y + 5)

Vertices of the image

a) (-3, 2)

b) (0, 2)

c) (0, 4)

d) (2, 4)

3. (x, y) → (x + 4, y)

Vertices of the image

a) (-1, -2)

b) (1, -2)

c) (3, -2)

4. (x, y) → (x + 6, y + 1)

Vertices of the image

a) (1, -1)

b) (1, -2)

c) (2, -2)

d) (2, -4)

e) (3, -1)

f) (3, -3)

g) (4, -3)

h) (1, -4)

5. (x, y) → (x, y - 4)

Vertices of the image

a) (0, -2)

b) (0, -3)

c) (2, -2)

d) (2, -4)

6. (x, y) → (x - 1, y + 4)

Vertices of the image

a) (-5, 3)

b) (-5, -1)

c) (-3, 0)

d) (-3, -1)

Explanation:

To identify each IMAGE you should perform the following steps:

List the vertex points of the preimage (the original figure) as ordered pairs.

Apply the transformation rule to every point of the preimage

List the image of each vertex after applying each transformation, also as ordered pairs.

1. (x, y) → (x + 3, y - 2)

The rule means that every point of the preimage is translated three units to the right and 2 units down.

Vertices of the preimage Vertices of the image

a) (-5,2) (-5 + 3, -1 - 2) = (-2, - 3)

b) (-5, 5) (-5 + 3, 5 - 2) = (-2, 3)

c) (-1, 4) (-1 + 3, 4 - 2) = (2, 2)

2. (x,y) → (x - 3, y + 5)

The rule means that every point of the preimage is translated three units to the left and five units down.

Vertices of the preimage Vertices of the image

a) (0, -3) (0 - 3, -3 + 5) = (-3, 2)

b) (3, -3) (3 - 3, -3 + 5) = (0, 2)

c) (3, -1) (3 - 3, -1 + 5) = (0, 4)

d) (5, -1) (5 - 3, -1 + 5) = (2, 4)

3. (x, y) → (x + 4, y)

The rule represents a translation 4 units to the right.

Vertices of the preimage Vertices of the image

a) (-5, -2) (-5 + 4, -2) = (-1, -2)

b) (-3, -5) (-3 + 4, -2) = (1, -2)

c) (-1, -2) (-1 + 4, -2) = (3, -2)

4. (x, y) → (x + 6, y + 1)

Vertices of the preimage Vertices of the image

a) (-5, -2) (-5 + 6, -2 + 1) = (1, -1)

b) (-5, -3) (-5 + 6, -3 + 1) = (1, -2)

c) (-4, -3) (-4 + 6, -3 + 1) = (2, -2)

d) (-4, -5) (-4 + 6, -5 + 1) = (2, -4)

e) (-3, -2) (-3 + 6, -2 + 1) = (3, -1)

f) (-3, -4) (-3 + 6, -4 + 1) = (3, -3)

g) (-2, -4) (-2 + 6, -4 + 1) = (4, -3)

h) (-2, -5) (-2 + 3, -5 + 1) = (1, -4)

5. (x, y) → (x, y - 4)

This is a translation four units down

Vertices of the preimage Vertices of the image

a) (0, 2) (0, 2 - 4) = (0, -2)

b) (0,1) (0, 1 - 4) = (0, -3)

c) (2, 2) (2, 2 - 4) = (2, -2)

d) (2,0) (2, 0 - 4) = (2, -4)

6. (x, y) → (x - 1, y + 4)

This is a translation one unit to the left and four units up.

Vertices of the pre-image Vertices of the image

a) (-4, -1) (-4 - 1, -1 + 4) = (-5, 3)

b) (-4 - 5) (-4 - 1, -5 + 4) = (-5, -1)

c) (-2, -4) (- 2 - 1, -4 + 4) = (-3, 0)

d) (-2, -5) (-2 - 1, -5 + 4) = (-3, -1)

8 0

3 years ago