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4vir4ik [10]
4 years ago
14

HELP ME IM TRYING TO MAKE MY PARENTS PROUD OF ME

Mathematics
1 answer:
s2008m [1.1K]4 years ago
4 0
Didn’t u already ask this question
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What’s the answer to this?
My name is Ann [436]

Answer:

A

Step-by-step explanation:

Linear functions are those whose graph is a straight line. A linear function has the following form. y = f(x) = a + bx. A linear function has one independent variable and one dependent variable. The independent variable is x and the dependent variable is y.

6 0
3 years ago
What is the answer to this?
JulsSmile [24]

Answer:

This parabola has a maximum of 10

Step-by-step explanation:

Since the y-value cannot increase past 10, the maximum value of this function would be 10.

5 0
2 years ago
Choose the best description of the roots of the equation 3x 2 - 4x + 5 = 0.
Naily [24]
For this case we have the following polynomial:
 3x ^ 2 - 4x + 5 = 0

 Using the resolver we have:
 x =  \frac{-b +/-  \sqrt{b^2 - 4ac}}{2a}
 Substituting values we have:
 x =  \frac{-(-4) +/-  \sqrt{(-4)^2 - 4*3*5}}{2*3} 


 x =  \frac{4 +/-  \sqrt{16 - 60}}{6}
 x =  \frac{4 +/-  \sqrt{-44}}{6}
 x =  \frac{4 +/-  \sqrt{-4*11}}{6}
 x =  \frac{4 +/-  2\sqrt{-11}}{6}
 x =  \frac{2 +/-  \sqrt{-11}}{3}
 x = \frac{2 +/- i\sqrt{11}}{3}
 Answer:
 
We observe that the solution to the quadratic equation are two imaginary roots.
7 0
3 years ago
The lengths of the sides of a triangle are in the extended ratio 5: 8:10. The perimeter of the triangle is 115 cm. What are the
leva [86]

Given :

  • The length of the sides of the triangle are in the ratio 5:8:10 .
  • The Perimeter of the Triangle is 115 cm.

To Find :

  • The length of the sides of the triangle.

Solution :

Let us assume the sides be 5x cm, 8x cm and 10x cm.

We know,

\qquad{ \bold{ \pmb{Sum \: of \: all \: sides \: of \: the \: triangle = Perimeter_{(Triangle)}}}}

So, Substituting the values :

\qquad { \dashrightarrow{ \sf{5x + 8x + 10x = 115}}}

\qquad { \dashrightarrow{ \sf{23x= 115}}}

\qquad { \dashrightarrow{ \sf{ \dfrac{23x}{23} = \dfrac{115}{23} }}}

\qquad { \dashrightarrow{ \bf{ x = 5 }}}

Therefore,

The length of the sides of the triangle are :

\qquad { \dashrightarrow{ \sf{ 5x \: cm= 5 \times 5 \: cm = \bf \: 25\: cm }}}

\qquad { \dashrightarrow{ \sf{ 8x \: cm= 8 \times 5 \: cm = \bf \: 40 \: cm }}}

\qquad { \dashrightarrow{ \sf{ 10x \: cm= 10 \times 5 \: cm = \bf \: 50 \: cm }}}

6 0
2 years ago
Helpppppp pleaseeeee
Crank
I think the answer is a
5 0
3 years ago
Read 2 more answers
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