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irina [24]
2 years ago
8

When solving negative one over five (x − 25) = 7, what is the correct sequence of operations? (5 points) a Multiply each side by

negative one over five, add 25 to each side b Multiply each side by 5, subtract 25 from each side c Multiply each side by negative one over five, subtract 25 from each side d Multiply each side by −5, add 25 to each side
Mathematics
1 answer:
german2 years ago
7 0

Answer:

Hello!!

When solving -\frac{1}{5} (x-25)=7, the correct sequence of operations would be...

Multiply each side by −5, add 25 to each side

Step-by-step explanation:

When completing the order of operations use PEMDAS Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).

Hope this helps!!

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An elevator is on the 20th floor. it goes down 11 floors and then up 5 floors .what floor is the elevator on noW.
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4 0
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The length of a rectangle is 3 inches more than its width. the area of the rectangle is 40 square inches. what is the length, in
IceJOKER [234]
Since width is the smaller value, set width=x. That wold mean that length=x+3. Since Area=width*length, 40=x(3+x). Distribute the x to give you 40=3x+x^2. Set the equation equal to 0 giving you x^2+3x-40=0. Factor the equation to give you (x+8)(x-5)=0. Set each factor equal to 0. x+8=0 gives you x=-8 & x=-5 gives you x=5. Since we're working with lengths of objects, it can't be negative. Therefore, your width is 5. To find length, substitute width into the original expression (x+3). Therefore, length is 5+3=8.
4 0
3 years ago
Let f(x) = -4x + 7 and g(x) = 10x - 6. Find f(g(x)).
Triss [41]
f(x)=-4x+7\\
g(x)=10x-6\\\\\Substitute\ x=10x-6\ to\ f(x)\\
f(g(x))=-4(10x-6)+7\\
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8 0
3 years ago
Everyone needs to get off of social and help us -_-
JulsSmile [24]
(x+2)(x+8)(x+k)=x^3+9x^2+6x-16

(x^2+10x+16)(x+k)=x^3+9x^2+6x-16

x^3+10x^2+16x+kx^2+10kx+16k=x^3+9x^2+6x-16

kx^2+10kx+16k=-x^2-10x-16

k(x^2+10x+16)=-x^2-10x-16

k=(-x^2-10x-16)/(x^2+10x+16)

k=-1

so the width is (x-1)




7 0
3 years ago
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