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Grace [21]
3 years ago
6

Help me out pls for quiz

Mathematics
1 answer:
dybincka [34]3 years ago
7 0
If you mean the third circle it should be 4inches since radius is 2inches (given on the drawing) and diameter is double the radius
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Aurelia wants to enlarge a 4 inch by 6 inch photo so that it has a width of 15 inches Use a ratio table to determine the new len
vichka [17]
Ok, this is a ratio problem; the ratio of the length to width is constant (and therefore equal):           4 /6 = 15 / x Now, with a ratio, we may do any allowable algebra operation:  cross-multiply, invert both sides, multiply or divide both sides by the same amount, etc. Let's cross-multiply:        4x = (15)(6)          x  = 90/4<span>          x = 22.5 in. </span>
3 0
3 years ago
Read 2 more answers
The area of the rectangular faces of the box are shown . What is the volume of the box
Gnoma [55]
Label the 3 distinct sides of the box.  I arbitrarily chose the letters a, b and c.
Use the info about areas as follows:

ab=54 in^2
ac=90 in^2
bc=60 in^2

Here you have 3 equations in 3 unknowns (a, b and c), which is enough info to use to determine a, b and c.  Then the volume of the box is a*b*c.

Example:  bc = 90, but c = 60/b.  You could subst. 60/b for c in the 2nd and 3rd equation, which will eliminate c completely and leave you with 2 equations in 2 unknowns.

Continuing this procedure, I determined that a=9, b=6 and c=10.  Thus, the volume of the box is V = 9*6*10 = 540 cubic inches (answer)

3 0
3 years ago
When Deven makes chocolate milk, he mixes 2 cups of milk with 3 tablespoons of chocolate syrup Here is a table that shows how to
Rzqust [24]

Answer: 1.5

Step-by-step explanation:

6 0
3 years ago
Which expression is equivalent to 2(7b + 5)?
DENIUS [597]

2(7b + 5) will equal to 14b+10

Explanation:

2 times 7b= 14b

2 times 5= 10

4 0
2 years ago
A pyramid with a square base is cut by a plane that is parallel to its base and is 2 units from the base. The surface area of th
icang [17]

Answer:

  6.83 units

Step-by-step explanation:

Let the height of the original pyramid be represented by h. Then the cut off top has a height of (h -2). The scale factor for the area is the square of the scale factor for height, so we have ...

  (height ratio)^2 = 1/2

  ((h -2)/h)^2 = 1/2

  (h -2)√2 = h . . . . . . square root; multiply by h√2

  h(√2 -1) = 2√2 . . . . add 2√2 -h

  h = (2√2)/(√2 -1) ≈ 6.8284 . . . units

The altitude of the original pyramid is about 6.83 units.

7 0
2 years ago
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