Remember for any two polygons
Area of polygons is directly proportional to square of sides
So
- BC²/XY²=135/15
- 15²/XY²=9
- (15/3)²=XY²
- XY=5in
#35
- HJ²/XY²=168/378
- 8²/XY²=0.44
- XY²=64/0.44
- XY²=145.45
- XY\approx 12+
We know from Euclidean Geometry and the properties of a centroid that GC=2GM. Now GM=sin60*GA=

. Hence CM=GC+GM=3*

. Now, since GM is normal to AB, we have by the pythagoeran theorem that:

Hence, we calculate from this that AC^2= 28, hence AC=2*

=BC. Thus, the perimeter of the triangle is 2+4*

.
Um idk sorry lol that’s way to hard for me
You need to subtract 25 by 18
x^2 + 6xy + 8y2
4x^2 + 3xy + 2y^2 - 5x^2 + 2xy + 6y^2
= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2
Combine like terms:
= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2
= (4x^2 + -5x^2) + (3xy + 3xy) + (2y^2 + 6y^2)
= -x^2 + 6xy + 8y^2