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2 years ago

Find the greatest common factor 18 and 33

Mathematics

2 answers:

klemol [59]2 years ago

6 0

<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ List all the factors for each value:

18: 18, 1, 9, 6, 3, 2

33: 11, 3, 33, 1

As you can see, the greatest COMMON (shared between both) factor is 3.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

allochka39001 [22]2 years ago

5 0

Answer:

the GCF (greatest common factor of the

#'s are 3

Step-by-step explanation:

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Use 2 unit multipliers to convert 4 square feet to square inches

allochka39001 [22]

Answer:

4 square feet is equal 576 square inches

Step-by-step explanation:

to convert 4 square feet to square inches

Now, We know that 1 feet = 12 inches

∴ $1^{2} \ feet = 12^2 \ inches\\1\ square\ feet= 144 \ square \ inches\\$

Now we need to find 4 square feet

$4 \times 1\ square\ feet= 4\times 144 \ square \ inches\\4 \ square\ feet= 576 \ square \ inches$

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3 years ago

Which equation is a related equation? x + 15 =24

AleksandrR [38]

Your answer would be A hope this helps!

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3 years ago

A half-acre building lot is five times as long as it is wide. What are its dimensions?

Gnoma [55]

we know that

A half-acre is equal to----------> $2,023.43\ m^{2}$

Let

x---------> the length side of the building lot

y--------> the width side of the building lot

A------> Area of the building lot

x=5y-------> equation 1

$A=2,023.43\ m^{2}$

$A=x*y$

$2,023.43=x*y$ --------> equation 2

substitute equation 1 in equation 2

$2,023.43=[5y]*y$

$5y^{2}= 2,023.43\\y^{2}= 404.686\\y= 20.11\ m$

<u>Find the value of x</u>

$x=5y---> x=5*20.11--> x=100.55 m$

therefore

<u>the answer is</u>

the dimensions of the building lot are 100.55 m* 20.11 m

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Ill edit this later to answer the question, but what is the question???

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