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artcher [175]
3 years ago
9

0.04 divided by 19 plzzzzzzzzzzz

Mathematics
2 answers:
Paraphin [41]3 years ago
6 0
0.00210526 yeeeeeeeee

e-lub [12.9K]3 years ago
5 0
0.04/ 19= 0.002105263157895

hope this helps :)
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7+7x=-70 what is the answer?
LenKa [72]

Answer: (-11)

Step-by-step explanation: 7+7x=-70

7-7+7x=-70-7

7x=-77

-77/7=-11

4 0
3 years ago
Change each of the following points from rectangular coordinates to spherical coordinates and to cylindrical coordinates.
FromTheMoon [43]

Answer and Step-by-step explanation: Spherical coordinate describes a location of a point in space: one distance (ρ) and two angles (Ф,θ).To transform cartesian coordinates into spherical coordinates:

\rho = \sqrt{x^{2}+y^{2}+z^{2}}

\phi = cos^{-1}\frac{z}{\rho}

For angle θ:

  • If x > 0 and y > 0: \theta = tan^{-1}\frac{y}{x};
  • If x < 0: \theta = \pi + tan^{-1}\frac{y}{x};
  • If x > 0 and y < 0: \theta = 2\pi + tan^{-1}\frac{y}{x};

Calculating:

a) (4,2,-4)

\rho = \sqrt{4^{2}+2^{2}+(-4)^{2}} = 6

\phi = cos^{-1}(\frac{-4}{6})

\phi = cos^{-1}(\frac{-2}{3})

For θ, choose 1st option:

\theta = tan^{-1}(\frac{2}{4})

\theta = tan^{-1}(\frac{1}{2})

b) (0,8,15)

\rho = \sqrt{0^{2}+8^{2}+(15)^{2}} = 17

\phi = cos^{-1}(\frac{15}{17})

\theta = tan^{-1}\frac{y}{x}

The angle θ gives a tangent that doesn't exist. Analysing table of sine, cosine and tangent: θ = \frac{\pi}{2}

c) (√2,1,1)

\rho = \sqrt{(\sqrt{2} )^{2}+1^{2}+1^{2}} = 2

\phi = cos^{-1}(\frac{1}{2})

\phi = \frac{\pi}{3}

\theta = tan^{-1}\frac{1}{\sqrt{2} }

d) (−2√3,−2,3)

\rho = \sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}+3^{2}} = 5

\phi = cos^{-1}(\frac{3}{5})

Since x < 0, use 2nd option:

\theta = \pi + tan^{-1}\frac{1}{\sqrt{3} }

\theta = \pi + \frac{\pi}{6}

\theta = \frac{7\pi}{6}

Cilindrical coordinate describes a 3 dimension space: 2 distances (r and z) and 1 angle (θ). To express cartesian coordinates into cilindrical:

r=\sqrt{x^{2}+y^{2}}

Angle θ is the same as spherical coordinate;

z = z

Calculating:

a) (4,2,-4)

r=\sqrt{4^{2}+2^{2}} = \sqrt{20}

\theta = tan^{-1}\frac{1}{2}

z = -4

b) (0, 8, 15)

r=\sqrt{0^{2}+8^{2}} = 8

\theta = \frac{\pi}{2}

z = 15

c) (√2,1,1)

r=\sqrt{(\sqrt{2} )^{2}+1^{2}} = \sqrt{3}

\theta = \frac{\pi}{3}

z = 1

d) (−2√3,−2,3)

r=\sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}} = 4

\theta = \frac{7\pi}{6}

z = 3

5 0
3 years ago
If f(x)=x^1/2-x and g(x)=2x^3-x^1/2-x, find f(x)-g(x)
inn [45]
X^1/2 - x
-2x^3 - x^1/2 - x

-2x^3 - 2x
i think this is it
6 0
3 years ago
Read 2 more answers
Suppose PV =NRT, where P=8, V=2X, N=2 and R=2X.you are given X=3. Solve for T
FromTheMoon [43]

Answer:  T = 4

Step-by-step explanation:

1. Write all the variables down

P = 8  V = 2X  N = 2  R = 2X  X = 3

2. Since you know that X = 3 substitute it in to find V and R

V = 2X = 2(3) = 6

R = 2X = 2(3) = 6

3. Find PV

PV = P x V

     = 8 x 6

     = 48

4. Find NRT

NRT = N x R x T

       = 2 x 6 x T

       = 12 x T

       = 12T

5. Find T

PV = NRT

48 = 12T

12T = 48

divide both sides by 12

  T = 48 ÷ 12

  T = 4

7 0
3 years ago
The math club wants to order t-shirts to recognize students who improved their performances in algebra I. Hot shirt charges $12.
horsena [70]

Answer:

1000

Step-by-step explanation:


3 0
4 years ago
Read 2 more answers
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