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KiRa [710]
3 years ago
10

In the triangle EFG,

Mathematics
1 answer:
MariettaO [177]3 years ago
7 0

Answer:

4.\ \sin E = \cos G

Step-by-step explanation:

Given

\triangle EFG

\angle F = 90^o --- right angle

Required

Which of the options is true

In a triangle, we have:

\angle E + \angle F + \angle G = 180^o --- angles in a triangle

Substitute \angle F = 90^o

\angle E + 90^o + \angle G = 180^o

Collect like terms

\angle E + \angle G = 180^o -90^o

\angle E + \angle G =90^o

This implies that E and G are complementary angles.

For complementary angles, E and G;

\sin E = \cos G and \sin G = \cos E

<em>Hence, (4) is true</em>

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