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motikmotik
3 years ago
8

Does the relation {(5,-2), (5,-8), (4,-6), (7,-1)} represent a function?

Mathematics
1 answer:
Sergio [31]3 years ago
5 0

Answer:

no, it does not

Step-by-step explanation:

if it was a function, all the x values would've been different, but since 5 is repeated, it is not a function.

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John di Silvestre obtained a loan to buy a cello for $8,400. He pays 12% exact interest on the loan for 146 days. What is the am
Svetradugi [14.3K]
<span>Normally when they tell you interest rate they say per annum meaning the percent interest rate for a year.

But in this problem they seem to say John pays 12% for a 146 day loan.

So interest = P * r / 100 = 8400 * 12/100 = $1,008.00
Maturity value = Principal + Interest = 8400 + 1008 = $9,408.00</span>
7 0
3 years ago
Complete the equation of the line through (-10,-7) and (-5, -9).<br>Use exact numbers,​
steposvetlana [31]

Answer:

y=\frac{-5}{2}*x + 18

Step-by-step explanation:

A line in 2-dimensional space has the following general equation:

y=m*x+b

Where m is the slope of the line, and b just a number

the slope can be obtaine using th following formula:

m=\frac{x_{2} - x_{1} }{y_{2} - y_{1}}

The point 2 is the one with the smallest value for x, that is (-10,-7) and the Point 1 is any other that belongs to the line, in this case, (-5,-9)

m=\frac{-5 - (-10) }{-9 - (-7)}

Resulting that \frac{-5}{2}

To find the other term we can use any other point, I prefer us the first one so...

We have the following equation:

-7=\frac{-5}{2}*(-10)+b

Resulting that b=18

I just have to eval the point (-10,-7) in the equation stated at the beginning  knowin that m was calculated previously.

8 0
3 years ago
Read 2 more answers
The equation of the line CD is (y-3)=-2(x-4). what is the scope of the line perpendicular to line CD
Delicious77 [7]

Answer:

y=-1/2x-5

Step-by-step explanation:

First we need to put (y-3)=2(x-4) in slope intercept form.

we need to do order of operations....

so we need to first do the parenthesis

x*2= 2x

2*-4= -8

y-3=2x-8

add 3 on both sides to isolate y

y= 2x-5

so now we know the y=mx+b form

this is one line...

now we need to find out what line is perpendicular.

Perpendicular lines have opposite reciprocals slopes.

y=-1/2x-5

8 0
3 years ago
3,200 people who owned a certain type of​ car,1,280 said they would buy that type of car again. What percent of the people surve
Phoenix [80]

Answer:

40%

Step-by-step explanation:

100%->3200

1%->32

1280÷32= 40 %

3 0
3 years ago
A county is considering rasing the speed limit on a road because they claim that the mean speed of vehicles is greater than 30 m
DochEvi [55]

Answer:

No, at alpha equals 0.10​, we do not have enough evidence to support the​ county's claim.

Step-by-step explanation:

We are given that a county is considering raising the speed limit on a road because they claim that the mean speed of vehicles is greater than 30 miles per hour.

A random sample of 15 vehicles has a mean speed of 31 miles per hour and a standard deviation of 4.7 miles per hour.

<em><u>Let </u></em>\mu<em><u> = true mean speed of the vehicles.</u></em>

SO, <u>Null Hypothesis</u>, H_0 : \mu \leq  30 miles per hour   {means that the mean speed of vehicles is lesser than or equal to 30 miles per hour}

<u>Alternate Hypothesis,</u> H_A : \mu > 30 miles per hour   {means that the mean speed of vehicles is greater than 30 miles per hour}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S.  = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean speed of 15 vehicles = 31 mph

             s = sample standard deviation = 4.7 mph

             n = sample of vehicles = 15

So, <em><u>test statistics</u></em>  =   \frac{31-30}{\frac{4.7}{\sqrt{15} } }  ~ t_1_4

                               =  0.824

<u><em>Hence, the value of test statistics is 0.824.</em></u>

<em />

<em>Now at 0.10 significance level, the t table gives critical value of 1.345 at 14 degree of freedom for right-tailed test. Since our test statistics is less than the critical value of t as 0.824 < 1.345, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.</em>

<em />

Therefore, we conclude that the mean speed of vehicles is lesser than or equal to 30 miles per hour which means that the county's claim is not supported.

4 0
4 years ago
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