QUESTION 3
The sum of the interior angles of a kite is
.
.
.
.
.
But the two remaining opposite angles of the kite are congruent.

.
.
.
.
QUESTION 4
RH is the hypotenuse of the right triangle formed by the triangle with side lengths, RH,12, and 20.
Using the Pythagoras Theorem, we obtain;





QUESTION 5
The given figure is an isosceles trapezium.
The base angles of an isosceles trapezium are equal.
Therefore
QUESTION 6
The measure of angle Y and Z are supplementary angles.
The two angles form a pair of co-interior angles of the trapezium.
This implies that;



QUESTION 7
The sum of the interior angles of a kite is
.
.
.
.
.
But the two remaining opposite angles are congruent.

.
.
.
.
QUESTION 8
The diagonals of the kite meet at right angles.
The length of BC can also be found using Pythagoras Theorem;




QUESTION 9.
The sum of the interior angles of a trapezium is
.
.
.
But the measure of angle M and K are congruent.
.
.
.
.
The solutions of the inequality is 7.99<x<8.01. I think this solutions means the radius of hole in the bolt or something along that, but I'm not sure.
1/112 or 0.008929 hope that helps
Answer:
x = 2.
Step-by-step explanation:
5[3(x + 4) − 2(1 − x)] − x − 15 = 14x + 55
5[3x + 12 - 2 + 2x] - x - 15 = 14x + 55
5[5x + 10] - x - 15 = 14x + 55
25x + 50 - x - 15 = 14x + 55 Now we subtract 14x from both sides:
25x + 50 - x - 15 - 14x = 14x - 14x + 55
10x + 50 - 15 = 55 Now we subtract 50, add 15 to both sides:
10x + 50 - 50 - 15 + 15 = 55 - 50 + 15
10x = 20
x = 2.
Answer: 6 students
Step-by-step explanation:
The teacher wants to give each student 2/3 of a slice of pizza but only has 4 slices to give.
If each student gets 2/3 out of 4 slices, the number of students receiving will be:
= Slices / proportion per slice
= 4 / 2/3
= 4 * 3/2
= 12/2
= 6 students