A reference point is a point in geometry or general which is used to determine or refer to another point. In reference to this point, measurements can be done. Like, a reference point in space is used to measure distance or displacement to another point. A reference point in time is used to measure the time interval of an event. A reference in space-time can be used to measure the speed or detect object's motion. Hence, the following points apply:
→A position from which to measure future distance
→a set of standard units for measuring displacement
→a method for determining the speed of an object
→a way to detect an object’s motion
A reference point provides a way/method to infer information about the object.
Describing motion from each frame of reference:
Since observer A is on one of the train's cars, he will find that he is at rest with respect to the train even when it is pulling away because, he is also moving with respect to the train.
Observer B on the stationary platform will observe that the train is pulling away from the station towards the right of the platform. as is described
Observer C will notice that the train is approaching him in the opposite direction at a speed which is the sum of the speeds at which both the train are traveling
If the conductor applies brakes on the train, since the platform is a stationary frame of reference. The motion will be observed as a simple decelerationg. he will observe that the force due to the brakes will cause the velocity of the train with respect to the train to decrease
Universal law of gravitation effects all objects alike . There will be a constant force of gravity acting on the train that will keep the train on its tracks. The tracks in turn exert a reaction force on the train. There will not be any affect on the train's motion as such( assuming that the train is moving along the tracks and gravitational force is exactly perpendicular)
Answer:
8.0s
Explanation:
45 km/h ÷ 3.6 = 12.5 m/s
t.v = d/t
vt/v = d/v
t = d/v = 100.0m /12.5 m/s = 8.0s
Hope this helps!!
Answer:
Case 1: <u>Pushing</u> Diagram 1
Leaning over and Pushing the heavy box from the floor, the push will be divided in to two parts, one is horizontal that can help the box move, and one is vertically downwards, which increases the downward force of the heavy object (an addition to the gravity) and thus increases friction, making it very hard to push. When you push at certain angle, you are exhibiting two forces as shown in diagram 1.
- Horizontal force acting along the plane.
- Vertical force downward perpendicular to the surface.
Case 2: <u>Pulling</u> Diagram 2
Pulling on a rope similar object at the same angle, the pull can be divided into two parts, one is horizontal that can help the box move, and one is vertically upwards, which decreases the downwards force of the box (a subtraction in the gravity) and thus decreases friction, making it very easy to pull. When you pull at a certain angle, you are exhibiting two forces as shown in diagram 2.
- Horizontal force acting along the plane.
- Vertical force upward perpendicular to the surface.
So, in the case of pushing, it adds an extra weight on the object, which results in difficulty to push that object at the same angle. In case of pulling, the upward perpendicular force, it tries to lift the object upward and divided the weight partially. Thus making it easier to move the object at same angle.
Answer:
Las presión ejercida por los tacos sobre el suelo es 900 libras por pulgada cuadrada.
Explanation:
Según la Física, comprendemos que la presión es igual a la fuerza dividida por área. En este caso, el peso de la persona dividida por área total de los tacos de los zapatos de golf suponiendo una distribución uniforme de la fuerza. Es decir:
(Eq. 1)
Donde:
- Presión, medida en libras por pulgada cuadrada.
- Peso de la persona, medida en libras.
- Cantidad de tacos en los zapatos, adimensional.
- Área del taco, medida en pulgadas cuadradas.
Si conocemos que 
, 
y 
, la presión es:
Las presión ejercida por los tacos sobre el suelo es 900 libras por pulgada cuadrada.
