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2 years ago

Im confused on how to do this

Physics

1 answer:

Grace [21]2 years ago

7 0

Explanation :

(1) No. of jumping jacks, $n=120$

time, $t=6\ minutes=360\ sec$

So, frequency is $f=\dfrac{n}{t}$

$f=\dfrac{120}{360\ sec}$

$f=0.33 Hz$

(2) The quarter spins 10 times every seconds

So, frequency $f=10\ Hz$

and the period of one cycle is, $t=\dfrac{1}{10\ Hz}$

$t=0.1\ sec$

(3) mass of block, $m=1.3\ Kg$

force constant of spring, $K=250\ N/m$

Time period of oscillations is given by :

$T=2\pi \sqrt{\dfrac{m}{k}}$

$T=2\pi \sqrt{\dfrac{1.3\ Kg}{250\ N/m}}$

So, $T=0.45\ sec$

Frequency, $F=\dfrac{1}{time\ period}$

$F=\dfrac{1}{0.45\ sec}$

$F=2.22\ Hz$

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g A change in the initial _____ of a projectile changes the range and maximum height of the projectile.

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Answer:

Velocity.

Explanation:

Projectile motion is characterized as the motion that an object undergoes when it is thrown into the air and it is only exposed to acceleration due to gravity.

As per the question, 'any change in the initial velocity of the projectile(object having gravity as the only force) would lead to a change in the range as well as the maximum height of the projectile.' To illustrate numerically:

Horizontal range: As per expression:

R= ( $u^{2}$ *sin2θ)/g

the range depending on the square of the initial velocity.

Maximum height: As per expression:

H= ( $u^{2}$ * $sin^{2}$ θ )/2g

the maximum distance also depends upon square of the initial velocity.

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3 years ago

A U-shaped tube open to the air at both ends contains some mercury. A quantity of water is carefully poured into the left arm of

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Answer:

a) $P=2450\ Pa$

b) $\delta h=23.162\ cm$

Explanation:

Given:

height of water in one arm of the u-tube, $h_w=25\ cm=0.25\ m$

Gauge pressure at the water-mercury interface,:

$P=\rho_w.g.h_w$

we've the density of the water $=1000\ kg.m^{-3}$

$P=1000\times 9.8\times 0.25$

$P=2450\ Pa$

Now the same pressure is balanced by the mercury column in the other arm of the tube:

$\rho_w.g.h_w=\rho_m.g.h_m$

$1000\times 9.8\times 0.25=13600\times 9.8\times h_m$

$h_m=0.01838\ m=1.838\ cm$

<u>Now the difference in the column is :</u>

$\delta h=h_w-h_m$

$\delta h=25-1.838$

$\delta h=23.162\ cm$

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Answer:

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3 years ago

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2 years ago

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Answer;

Amount of time the two substances are in contact

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