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Andreas93 [3]
3 years ago
9

Im confused on how to do this

Physics
1 answer:
Grace [21]3 years ago
7 0

Explanation :

(1) No. of jumping jacks, n=120

time, t=6\ minutes=360\ sec

So, frequency is f=\dfrac{n}{t}

f=\dfrac{120}{360\ sec}

f=0.33 Hz

(2) The quarter spins 10 times every seconds

So, frequency f=10\ Hz

and the period of one cycle is, t=\dfrac{1}{10\ Hz}

t=0.1\ sec

(3) mass of block, m=1.3\ Kg

force constant of spring, K=250\ N/m

Time period of oscillations is given by :

T=2\pi \sqrt{\dfrac{m}{k}}

T=2\pi \sqrt{\dfrac{1.3\ Kg}{250\ N/m}}

So, T=0.45\ sec

Frequency, F=\dfrac{1}{time\ period}

F=\dfrac{1}{0.45\ sec}

F=2.22\ Hz

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A motorist drives north for 35.0 minutes at 85.0 kph. He then stops for 15.0 minutes. The motorist then drives 130.0 km in 2.0 h
o-na [289]

Answer:

A. 216.36 \frac{km}{h}

B. 96.56 \frac{km}{h}

Explanation:

Let s_{1} be the distance in first part.

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Let s_{2} be the distance in first part.

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Average velocity = \frac{Total displacement}{Total time}

When second leg of the trip is

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Average velocity = \frac{[tex] s_{1} + s_{2}}{Total time}  [/tex]

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Average velocity =216.36 \frac{km}{h}

B. Toward south

Average velocity = \frac{[tex] s_{1} - s_{2}}{Total time}  [/tex]

Average velocity = \frac{130-49.58}{0.25+0.58}

Average velocity =96.56 \frac{km}{h}


3 0
3 years ago
I need help/this is a major grade
Debora [2.8K]

Answer:

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