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Zepler [3.9K]
2 years ago
7

Sasha is listening to music. He speeds up the music and the music becomes quieter. Which pair of longitudinal waves best represe

nts the music before and after Sasha speeds up the music?
Physics
1 answer:
Romashka [77]2 years ago
8 0

Answer:

thw poopoo0[ wavez

Explanation:

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A level of
Wittaler [7]

Answer:

x = 2 meters.

Explanation:

Let the position (distance) of fulcrum to the load be x.

Given the following data;

Load = 40 kg

Effort (force) = 40 Newton

Effort arm = 4 - x

To find the position of the fulcrum, we would use the expression;

Effort * effort arm = load * load arm

40 * (4 - x) = 40 * x

160 - 40x = 40x

160 = 40x + 40x

160 = 80x

x = 160/80

x = 2 meters

Therefore, the position (distance) of fulcrum to the load is 2 meters.

7 0
3 years ago
What is the wavelength of an earthquake wave if it has a speed of 4 km/s and a frequency of 7 Hz?
damaskus [11]

Answer: 0.571 km/s

λ = v/f

λ = 4/7

λ = 0.571 km/s


7 0
4 years ago
How long is a string under 240 N of tension whose mass is 0.086 kg if a wave travels through it at a speed of 12 m/s?
Darina [25.2K]

Answer:

The length of the string is 0.051 meters

Explanation:

It is given that,

Tension in the string, T = 240 N

Mass of the string, m = 0.086 kg

Speed of the wave, v = 12 m/s

The speed of the wave on the string is given by :

v=\sqrt{\dfrac{T}{M}}

M is the mass per unit length of the string i.e. M = m/l.......(1)

So, M=\dfrac{T}{v^2}

M=\dfrac{240\ N}{(12\ m/s)^2}

M = 1.67 kg/m

The length of the string can be calculated using equation (1) :

l=\dfrac{m}{M}

l=\dfrac{0.086\ kg}{1.67\ kg/m}

l = 0.051 m

So, the length of the string is 0.051 meters. Hence, this is the required solution.

6 0
3 years ago
Friction is defined as *
den301095 [7]

Answer:

O a force that opposes motion

5 0
3 years ago
A song is playing on a radio. Which of the following best
PtichkaEL [24]
One is the best choice for an answer.
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3 years ago
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