Would it be 3x times as far and the second answer 2x as far
They are traveling at right angles to each other so we can say one is traveling north to south and the other west to east. Then we can say that there positions, y and x are:
y=150-600t x=200-800t
By using the Pythagorean Theorem we can find the distance between these two planes as a function of time:
d^2=y^2+x^2, using y and x from above
d^2=(150-600t)^2+(200-800t)^2
d^2=22500-180000t+360000t^2+40000-320000t+640000t^2
d^2=1000000t^2-500000t+62500
d=√(1000000t^2-500000t+6250)
So the rate of change is the derivative of d
dd/dt=(1/2)(2000000t-500000)/√(1000000t^2-500000t+6250)
dd/dt=(1000000t-250000)/√(1000000t^2-500000t+6250)
So the rate depends upon t and is not a constant, so for the instantaneous rate you would plug in a specific value of t...
...
To find how much time the controller has to change the airplanes flight path, we only need to solve for when d=0, or even d^2=0...
1000000t^2-500000t+62500=0
6250(16t^2-8t+1)=0
6250(16^2-4t-4t+1)=0
6250(4t(4t-1)-1(4t-1))=0
6250(4t-1)(4t-1)=0
6250(4t-1)^2=0
4t-1=0
4t=1
t=1/4 hr
Well technically, the controller has t<1/4 because at t=1/4 impact will occur :)
Something bout, something bout you, makes me wanna do things that i shouldnt
Answer:
x=-17,y=3
Step-by-step explanation:
x+y=-14
x=x
y=x+20
x+(x+20)=-14
2x+20=-14
2x=-14-20
2x=-34
x=-34/2
x=-17
y=-17+20
y=3
Answer:
Right Isosceles
Step-by-step explanation:
First, let's see if this triangle is Acute, Obtuse or Right.
We see that PB and QB are perpendicular lines, meaning that they form a right angle. Therefore, triangle PQB is a right triangle.
Next, let's see if this triangle is equilateral, isosceles or scalene. PB and QB are congruent side lengths but PQ is not congruent to either PB or QB. Therefore, because two of the side lengths are congruent to each other and one is not, then triangle PQB is a isosceles triangle.
In conclusion, triangle PQB can be categorized as a right isosceles triangle.
Hope this helps!
