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s2008m [1.1K]
3 years ago
7

What is the degree of the following polynomial x²y³ + z

Mathematics
1 answer:
Yakvenalex [24]3 years ago
7 0
The answer on top of me is correct
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Graph the solution on the number line |x-3| <5
Anettt [7]

Answer:

-2<x<8

see below for graph

Step-by-step explanation:

First, we need to solve the inequality.

Inequality: |x-3|<5

Split into two equations:

x-3<5

x-3>-5 (notice how the sign is flipped when we make the number negative)

let's start with x-3<5

add 3 to both sides

x<8

now

x-3>-5

add 3 to both sides

x>-2

The graph is below

the intersection is the solution.

Notice how I made the maroon line go to the right- which shows that it's greater than (for x>-2) and the silver line go to the left, which shows that it's less than (for x<8)

the equation is -2<x<8

Hope this helps!

8 0
3 years ago
Diego solved an equation by multiplying both sides of the equation by 6. Then he checked that 6 is the correct solution by subst
Nikolay [14]
Based on the given condition Diego utilized, it can be said that he used multiplication property when he multiplied both sides of the equation by 6 and then substitution property when he substituted 6 to the original equation.
(c) Multiplication property of equality and substitution property of equality
7 0
3 years ago
-2/5x+6=8 can you help me
ale4655 [162]
If you would like to solve the equation - 2/5 * x + 6 = 8, you can do this using the following steps:

- 2/5 * x + 6 = 8
- 2/5 * x = 8 - 6
- 2/5 * x = 2    /*(-5/2)
x = 2 * (- 5/2)
x = - 5

The correct result would be -5.
7 0
3 years ago
Read 2 more answers
A segment bisector makes two segments that have equal length?
dedylja [7]
True by definition <span>In general 'to bisect' something means to cut it into two equal parts. The 'bisector' is the thing doing the cutting </span>
6 0
3 years ago
Determine the end behavior of each rational function below. Graph each function on the graphing calculator, and
melomori [17]

Answer:

a) End behavior: As → ∞, () → . As → −∞, () → .

Looking at the ends of the graph, as goes to ∞ or −∞, gets

closer to .

b) End behavior: As → ∞, () → . As → −∞, () → .

Looking at the ends of the graph, as x goes to ∞ or −∞, gets

closer to .

c) End behavior: As → ∞, () → ∞, and as → −∞, () → −∞.

Looking at the ends of the graph, as goes to ∞, continues to increase

toward ∞, and as x goes to −∞, continues to decrease toward −∞.

Obs:. Graphics are attached

5 0
3 years ago
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