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VLD [36.1K]
3 years ago
5

Please help asap 32 pts

Mathematics
1 answer:
Ede4ka [16]3 years ago
8 0

x - number of miles

0.19x+75\geq100\qquad|\text{subtract 75 from both sides}\\\\0.19x\geq25\qquad|\text{divide both sides by 0.19}\\\\x\geq132

<h3>Answer: d) x ≥ 132</h3>
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At a New Car Dealership, a particular model comes in 3 different trim levels (CX, DX,
xxMikexx [17]

Answer:

B. 48

Step-by-step explanation:

Multiply all the numbers of choices together.

trim levels: 3

colors: 4

interior: 4

number of combinations = 3 * 4 * 4 = 48

7 0
3 years ago
Read 2 more answers
A homogeneous rectangular lamina has constant area density ρ. Find the moment of inertia of the lamina about one corner
frozen [14]

Answer:

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Step-by-step explanation:

By applying the concept of calculus;

the moment of inertia of the lamina about one corner I_{corner} is:

I_{corner} = \int\limits \int\limits_R (x^2+y^2)  \rho d A \\ \\ I_{corner} = \int\limits^a_0\int\limits^b_0 \rho(x^2+y^2) dy dx

where :

(a and b are the length and the breath of the rectangle respectively )

I_{corner} =  \rho \int\limits^a_0 {x^2y}+ \frac{y^3}{3} |^ {^ b}_{_0} \, dx

I_{corner} =  \rho \int\limits^a_0 (bx^2 + \frac{b^3}{3})dx

I_{corner} =  \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}

I_{corner} =  \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Thus; the moment of inertia of the lamina about one corner is I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

7 0
3 years ago
1-2 Cos²25°÷(1-2sin²25)<br>​
shusha [124]

Answer:

have a good one

Step-by-step explanation:

6 0
2 years ago
I need to know the answer to my question
stiks02 [169]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2789579

_______________


Solve the incomplete quadratic equation:

\mathsf{3m^2-24m=0}\\\\ \mathsf{3m\cdot m-3m\cdot 8=0}\\\\ \mathsf{3m\cdot (m-8)=0}\\\\ \begin{array}{rcl} \mathsf{3m=0}&~\textsf{ or }~&\mathsf{m-8=0}\\\\ \mathsf{m=0}&~\textsf{ or }~&\mathsf{m=8} \end{array}


Solution set:   S = {0,  8}.


I hope this helps. =)

4 0
3 years ago
Abigail has 16 shoes use repeated subtraction to show how many pairs of shoes Abigail has
erik [133]

Hello!

Here is how we solve this question.

We know that 2 shoes = 1 pair

So we subtract 2 from 16 until we reach 0, and count how many times we subtracted.

16-2=14

14-2=12

12-2=10

10-2=8

8-2=6

6-2=4

4-2=2

2-2=0

After we do repeated subtraction we find that Abigail has 8 pairs of shoes!

Hope this helps you with your question.

7 0
3 years ago
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