The given equation with t -1 is:
(t – 1)^3 + 6 (t – 1)^2 + 12 (t – 1) + 8
Expand each term before combining for easier visualization:
(t – 1)^3 = t^3 – 3 t^2 + 3t – 1
6 (t – 1)^2 = 6 t^2 – 12 t + 6
12 (t – 1) = 12 t - 12
Then substitute and combine:
-> t^3 – 3 t^2 + 3t – 1 + 6 t^2 – 12 t + 6 + 12 t – 12 + 8
t^3 + 3 t^2 + 3 t + 1 (ANSWER)
Answer:
X > -4
Step-by-step explanation:
Collect the like terms which literally leaves you with -x<4
Then just changes the signs, hence the answer.
Please mark brainliest!
Answer:
Line "L" has the slope of 1 and line "K" has the slope of 2.
In order to graph a line with the slope of 
think of the numerator as the "rise" (how much you move up/down on the y-intercept) and the denominator as the "run" (how much you move to the side on the x-intercept)
Step-by-step explanation:
A slope of "1" is simply 
so you rise up one and move to the right once. This clearly demonstrated on line "L".
A slope of "2" is 
so you rise up two and move to the right once, as is demonstrated on line "K".
For the 2nd question, line "A" will have a slope of therefore it will move up once and then to the side three times. It will look like the image attached to this answer.
I hope this helped! Feel free to ask questions if needed!
The initial value is 3 (when x=0), and the multiplier is 2, when x=2. The equation can be written as
.. y = 3*(2^(x/2))
