PLZ help on 1 and 2 ASAP have to turn in homework now.
1 answer:
<h2>1.</h2>
- 180° . . . . linear angles are supplementary
- 3x . . . 180°
- 180°-3x
- PLM . . . . an exterior angle of a triangle is equal to the sum of the opposite interior angles
- 2x+72° . . . x
- 27°
<h2>2.</h2>
- CAB . . . . alternate interior angles where a transversal crosses parallel lines are congruent
- ACB . . . . the sum of angles of a triangle is 180°
- 3x . . . 180°
- 27°
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Your answer is D. paralllel Lines
Your Anwser is Compound Interest
Answer:
x^2/400 + x^2/625
(x-0)^2/400) +(y-0^2/625)
x^2=400
X=sqrt. 400
x = 20
y^2=625
y = sqrt. 625
y= 25
a^2-c^2=b^2
sqrt 400-625 = c
20-25=c
The correct answer is c=-5
(-5,0)
(5,0)
Step-by-step explanation:
Answer:
(6-2)×180 = 720
101+154+72+123+145+x=720
595 + x = 720
x = 720-595
x= 125