PLZ help on 1 and 2 ASAP have to turn in homework now.

Mathematics

1 answer:

dezoksy [38]2 years ago

3 0

180° . . . . linear angles are supplementary
3x . . . 180°
180°-3x
PLM . . . . an exterior angle of a triangle is equal to the sum of the opposite interior angles
2x+72° . . . x
27°

CAB . . . . alternate interior angles where a transversal crosses parallel lines are congruent
ACB . . . . the sum of angles of a triangle is 180°
3x . . . 180°
27°

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A scatter plot with a line is shown below. Which statement is most likely correct about the line?

Savatey [412]

Answer: A

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1 year ago

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Plzzzzzzzz! A suitcase lock has a code 4 symbols long. The symbols on the lock are a star, a square, a circle, a triangle, a lin

34kurt

Answer:

$\dfrac{1}{30}$

Step-by-step explanation:

6 symbols and 4-symbol code so number of combinations wich doesn't contain the same symbol twice would be:

6•5•4•3 = 360

If code starts with a star followed by triangle that means only one posibility for first two symbols and code doesn't containing the same symbol twice means that left 4 symbols for next two.

So number of combinations of code starting with a star followed by triangle and doesn't containing the same symbol twice will be:

1•1•4•3 = 12

The probability that a randomly chosen code starts with a star followed by triangle and doesn't contain the same symbol twice:

$\dfrac{1\cdot1\cdot4\cdot3}{6\cdot5\cdot4\cdot3}=\dfrac{1\cdot1}{6\cdot5}=\dfrac{1}{30}$