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2 years ago

What is the mean absolute?

Mathematics

1 answer:

alex41 [277]2 years ago

7 0

Answer:

mean absolute deviation is <em>8</em>

Step-by-step explanation:

to find mean absolute deviation, you subtract your mean from each of your values, and make them all positive, (even if u get a negative..)

then you add all your new answers up and divide by how many numbers there are (basically just find mean of your new set of data...)

<em>Hope this helps you in the future!!</em>

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Can someone help me solve v + 17< -52

irina [24]

Answer:

steps to solve

subtract 17 from both sides
then you add because two negatives become a positive

5 0

2 years ago

Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2.

insens350 [35]

Answer:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

Step-by-step explanation:

Given

$p(x) = \frac{x^2-2x-3}{x+2}$ -- Missing from the question

Required

The behavior of the function around its vertical asymptote at $x = -2$

$p(x) = \frac{x^2-2x-3}{x+2}$

Expand the numerator

$p(x) = \frac{x^2 + x -3x - 3}{x+2}$

Factorize

$p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}$

Factor out x + 1

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

$x -> -2^{-}$ Say x = -3

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

$p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12$

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

$x->-2^{-}, p(x)->-\infty$

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: $x>-2$

Say x = -2.1

$p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1$

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

$x->-2^{+}, p(x)->-\infty$

So, the behavior is:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

6 0

2 years ago

A conducter is mapping a trip and records the distance the trian travels over a certain time intervals

jeyben [28]

Answer:

cool

Step-by-step explanation:

6 0

2 years ago

Are both a function or not ?

Ganezh [65]

Answer:

Here

Step-by-step explanation:

Domain : (-∞,∞)

Range : (-∞,∞)
Both functions generally are the same and yes both are functions.

One is the data set of a function and one is the equation...

Sorry if this isn't what you were looking for...

8 0

1 year ago

Determine wether the function is increasing, decreasing, or constant

evablogger [386]

Answer:

decreasing

Step-by-step explanation:

"Increasing" means the graph is going up from left to right.

"Decreasing" means the graph is going down from left to right.

"Constant" means the graph is "flat" (this is not a technical term) it is keeping the same y value, neither going up nor going down.

What can be super confusing is the

(2.2, 5) mentioned in the question. THIS IS NOT A POINT. It is an interval and points and intervals unfortunately have the same notation sometimes.

An "interval" is a section of the graph, here: FROM 2.2 not including 2.2, TO 5 not including 5. These are like the address on the x-axis. If you look at your graph at 2.2 on the x-axis, it is a peak(relative maximum) and it goes down to the right to where x is 5 where it bottoms out (relative minimum) So on that interval, from 2.2 to 5, the graph is DECREASING.

4 0

1 year ago