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2 years ago

T=4U/E SOLVE FOR U please please please help please thank you

1 answer:

3 0

TE/4 =U
Step by step
You multiply both sides by E to get rid of it then you have TE =4U and then u divide it by 4 and get TE/4 =U

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the table shows the number of yards a football player runs in each quater of a game find the mean number of yards the player run

zalisa [80]

We know the number of yards run per quarter:

Quarter 1: -2 yards
Quarter 2: 14 yards
Quarter 3: -18 yards
Quarter 4: -6 yards

$\text{Mean number of yards run} = \frac{\text{Sum of yards run across quarters}}{\text{Total number of quarters}}$

Sum of yards run across quarters = (-2) + 14 + (-18) + (-6) = -12

Total number of quarters = 4

⇒ $\text{Mean number of yards run} = \frac{\text{Sum of yards run across quarters}}{\text{Total number of quarters}}$

⇒ $\text{Mean number of yards run} = \frac{-12}{4}$ = -3

Hence, he ran -3 yards per quarter

7 0

3 years ago

What is 2,208 rounded to the nearest hundred

icang [17]

2208 rounded to the nearest hundred would be 2200 because the number beside 2 is 0 and that makes the number stay the same and everything after it would be 0 so the answer is 2200

4 0

3 years ago

Read 2 more answers

The coach took a digital photo of the new cycling team bike. She sent a 4 cm-by-6 cm photo to each team

erastova [34]

Answer:

1. 9 cm

2. 50%

3. Assuming the photo is a rectangle, the answer would be 90 degrees on every angle (in a dilation, angle measurements are congruent).

Step-by-step explanation:

1. The long side is clearly the 6 cm side. multiply it by 1.5x (150%) and you get 9.

2. 2 is 50% of 4 and 3 is 50% of 6.

3. Assuming the photo is a rectangle, the answer would be 90 degrees on every angle (in a dilation, angle measurements are congruent).

6 0

3 years ago

What is the average of all interfere from 11 to 35

diamong [38]

Answer:

I'm not so sure what you mean from your question but if we discussed the Average of 11 and 35( positive integers), we would say that it's 23.

8 0

2 years ago

Surveys indicate that two-thirds of all voters in Ward 5 plan on choosing Spike Jones for commissioner. If there are 500 voters

olya-2409 [2.1K]

Answer:

333 people of ward 5 are going to be voting for Spike Jones.

Solution:

We have been given that two-thirds of all voters in Ward 5 plan on choosing Spike Jones for commissioner.

There are 500 voters in Ward 5.

Since 2/3 of all voters in Ward 5 are voting for Spike Jones the remaining 1/3 will not be voting for him.

To find out how many people in ward 5 are exactly voting for Spike Jones. We need to calculate how much is two thirds of 500 is.

This is done as follows:

$\begin{array}{l}{\frac{2}{3} \times 500} \\\\ {=\frac{1000}{3}} \\\\ {=333.334}\end{array}$

Since people cannot be denoted in decimal points we have to round it off to a whole number. That’s is 333.

Therefore 333 people of ward 5 are going to be voting for Spike Jones.

4 0

3 years ago