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loris [4]
3 years ago
15

To raise money for after-school programs at an elementary school, a group of parents is holding a weekend of games in a communit

y center. They charge $8 per person for entry into the event. The group would like to earn at least $600, after paying for the cost of renting the space, which is $40 an hour. If x represents the number of entry tickets sold and y the hours of space rental, which inequality represents the constraints in the situation? Group of answer choices 8x-40y 600 8x-40y > 600
Mathematics
1 answer:
frez [133]3 years ago
7 0

Answer:

8x-40y\geq 600 and x>0,y>0

Step-by-step explanation:

The number of people is x and the number of hours they are present in the space is y.

Per person entry cost is $8.

Per hour cost of rent is $40.

They plan to earn a minimum of $600.

Donations by all the people entering the space is 8x

Total cost of renting the space is 40y which will be subtracted from the total amount of donations.

The inequality that represents the situation is 8x-40y\geq 600 and x>0,y>0.

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Answer:

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g Suppose, for simplicity, that three main parts of a laptop are CPU, RAM, and hard drive;so if one of theses components fails,
aleksley [76]

Answer:

The average yearly replacement cost is approximately $32,211,500

Step-by-step explanation:

 Exponential Distribution

P(X < x) = 1 - e -x/

P(X < x) = 1 - e^{\dfrac{-x}{\mu}}

For the CPU, μ = 3 years

The probability that a CPU fails in less than 1 year is therefore;

P(C) = P(X < 1) = 1 - e^{\dfrac{-1}{3}} \approx 0.2835

For the RAM, μ = 2 years

The probability that a RAM fails in less than 1 year is therefore;

P(R) = P(X < 1) = 1 - e^{\dfrac{-1}{2}} \approx 0.3935

For the hard drive, μ = 5 years

The probability that a hard drive fails in less than 1 year is therefore;

P(H) = P(X < 1) = 1 - e^{\dfrac{-1}{5}} \approx 0.1813

The probability that either a CPU, or a RAM or a hard drive fails in 1 year so that a replacement is required, P(C ∪ R ∪ H), is given as follows;

P(C ∪ R ∪ H) = P(C) + P(R) + P(H) - P(C∩R) - P(C∩H) - P(R∩H) + P(C∩R∩H)

∴ P(C ∪ R ∪ H) = 0.2835 + 0.3935 + 0.1813 - (0.2835 × 0.3935) - (0.2835 × 0.1813) -(0.3935 × 0.1813) + (0.2835 × 0.3935 × 0.1813) ≈ 0.64423

∴ P(C ∪ R ∪ H) ≈ 0.64423

There is a 0.64423 chance that a laptop will require replacement

For 100,000 laptops sold a year and a replacement cost of $500 per laptop, we have;

The average yearly replacement cost, 'Cost' is given as follows;

Cost = 500 × 100,000 × 0.64423 = 32,211,500

The average yearly replacement cost, Cost ≈ $32,211,500

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