Question

Chem deposited $115.00 in a savings account. Each week thereafter, he

Answer 1

Answer:

Part a) $y=35x+115$

Part b) $\ 1,165$

Step-by-step explanation:

Part a)

Let

x -----> the number of weeks

y ----> the total amount Chem has deposited in a saving account

we know that

The equation of a line in slope intercept form is

$y=mx+b$

where

m is the rate or slope of the linear equation

b is the y-intercept of the linear equation or initial value (value of y when the value of x is equal to zero)

In this problem we have that

The rate or slope is equal to

$m=35\frac{\ }{week}$ -----> amount deposited by Chem each week

The y-intercept or initial value is

$b=\ 115$ ----> amount deposited originally in the saving account

substitute the values

$y=35x+115$

Part b) How much has Chem deposited 30 weeks after his initial deposit?

For x=30 weeks

substitute in the equation

$y=35(30)+115$

$y=\ 1,165$