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ra1l [238]
3 years ago
6

Find x if x-8=2(x+4)

Mathematics
2 answers:
Fofino [41]3 years ago
4 0

Answer:

x=-16

Step-by-step explanation:

x-8=2(x+4)\\x-8=2x+8\\-x=16\\x=-16

kondor19780726 [428]3 years ago
3 0

Answer:

x= -16

Step-by-step explanation:

x-8=2(x+4)

x-8=2x+8

-x=16

x=-16

-16-8= -24        2(-16+4)= -24

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z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562  

p_v =P(z>2.562)=0.0052  

So the p value obtained was a very low value and using the significance level given \alpha=0.02 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that at 2% of significance the proportion of voters that favored construction is higher than 0.63 or 63%.

Step-by-step explanation:

Data given and notation

n=1700 represent the random sample taken

\hat p=0.66 estimated proportion of voters that favored construction

p_o=0.63 is the value that we want to test

\alpha=0.02 represent the significance level

Confidence=98% or 0.98

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that percentage of residents who favor construction is more than 63%.:  

Null hypothesis:p \leq 0.63  

Alternative hypothesis:p > 0.63  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.02. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.562)=0.0052  

So the p value obtained was a very low value and using the significance level given \alpha=0.02 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that at 2% of significance the proportion of voters that favored construction is higher than 0.63 or 63%.

7 0
3 years ago
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